# GRE Perfect Math Score Challenge

The Revised GRE is a long, grueling test. To get a perfect score on the quantitative section (a 170) you will not only have to answer the difficult questions correctly, but you will also have to answer all of the easy ones. Nonetheless, I’ve focused on the difficult questions for the 170-challenge. I can’t promise a perfect correlation, but something tells me that if you can answer all five of these questions correctly in less than 10 minutes, you are well on your way to a perfect score.

Of course missing a few hardly precludes a perfect score. But make sure you learn from the ones you miss to make sure you don’t make similar mistakes in the future. And if time is a problem, remember the Magoosh GRE product has plently of questions to help you hone your chops—both from a pacing and a conceptual standpoint.

Good luck, and feel free to post your answers. Let’s see who the first perfect score will be!

1. If s and t are both primes, how many positive divisors of v are greater than 1, if v is an integer?

(A)  two

(B)  three

(C)  five

(D) six

(E)  eight

2. A quadrilateral has a perimeter of 16. Which of the following alone would provide sufficient information to determine the area of the quadrilateral. Choose ALL that apply.

[A]  The quadrilateral contains equal sides

[B]  The quadrilateral is formed by combining two isosceles right triangles

[C]  Two pairs of congruent angles are in a 2:1 ratio

[D] The width is 4o% of the length and all angles are of equal measure

[E]  If the perimeter was decreased by 50%, the area would decrease to 25% of the original

3. Product Question: Triangle in a Parabola

http://gre.magoosh.com/questions/2192

4. If x is an integer, and 169 < < 324, which of the following is the sum of all values of x?

(A)  61

(B)  62

(C)  75

(D) 93

(E)  None of the above.

5. x = 350,000

y = 45,000

Column A Column B
The total number of positive divisors of x The total number of positive divisors of y

1. The quantity in Column A is greater
2. The quantity in Column B is greater
3. The two quantities are equal
4. The relationship cannot be determined from the information given

[Note from our intern, Dylan: “I can do multivariable calculus, and got 2/5 on these in 10 minutes. These guys are tricky. :P”]

## Explanation Video #3

http://gre.magoosh.com/questions/2192

## Explanation Video #5

### 78 Responses to GRE Perfect Math Score Challenge

1. Tova June 13, 2020 at 10:50 am #

Hi,

Could you post the correct answers so we could check ourselves?

Thanks.

• Magoosh Test Prep Expert July 24, 2020 at 9:16 am #

Hi Tova,

You can see the answers and explanation for each question at the bottom of the post. We link to an explanation video for each question.

2. mohith August 16, 2019 at 4:17 am #

first question – you ask s^3 * t^3 – this implies that s and t are 2 different numbers and not the same number.

• Magoosh Test Prep Expert August 18, 2019 at 1:50 pm #

Hi Mohith!

Yes, two variables indeed can be the same number. If the text doesn’t specify they are distinct/unique/different, you cannot assume they are. These are the types of mathematical truths the GRE will aim to throw at you, so taking the question literally is a very good plan. We’re not told that s and t are unique/different, so it suggests that they could be the same number.

3. Ashu October 16, 2018 at 4:41 am #

The area does not reduce BY 25%, it reduces TO 25% of the original as per your explanation of Q2.

• Magoosh Test Prep Expert October 24, 2018 at 9:43 am #

Hi Ashu,

Thanks for pointing this out! You are absolutely right, the question should read “reduces to 25% of the original.” I’m going to send this along to our content improvement team so that they can take a look at it 🙂 Thanks again!

• Magoosh Test Prep Expert November 2, 2018 at 1:49 pm #

Hi Ashu! Just wanted to let you know that we made this change 🙂

4. Vikhyat Khare July 27, 2018 at 4:41 pm #

B is correct.
Suppose the the two isosceles right triangles have sides of (x, x and xsqrt2) and (y, y and ysqrt2) [This is the only ratio that the sides in an isosceles right triangle can be]. Then the only ways that a quadrilateral can be formed by combining them are-

1) The two hypotenuse are equal, i.e, xsqrt2 = ysqrt2 which implies that x = y and the quadrilateral will be a square and we will be able to find the area.

2) Side x is the same size as the hypotenuse ysqrt2 of the other triangle (or the other way round forming a trapezium). In this case x = y sqrt2 —–eqn 1
And, summing all sides, x + xsqrt2 + y + y = 16 ——eqn 2
Solving these equations will give us x and y and then we can find the areas of the two triangles and thus the quadrilateral.

• Magoosh Test Prep Expert August 1, 2018 at 8:36 am #

Your two possibilities both work. The problem, of course, is that there are two possibilities. So without knowing which possibility we’re dealing with, B alone doesn’t provide us enough information to determine the area of the quadrilateral. It only narrows things down to 2 possibilities.

5. Ila June 1, 2018 at 4:25 am #

1) B
2) A,B,D
3) 1/2
4)E
5) A

6. Rohan Goyal July 17, 2017 at 9:38 pm #

Very easy questions. I am a 9th grader, all of them took me 7 mins. I got all correct.

• Magoosh Test Prep Expert July 18, 2017 at 1:11 pm #

Great job, Rohan! You are a math maven 🙂

7. Sindhu June 24, 2017 at 8:40 am #

I don’t understand why B is not an option for question two. Even if it was a rhombus, you would be able to figure out the hypotenuse as a*square root of 2. Then find a by solving 2*(a+a*root2) equal perimeter of 16. Then you know the height and length of the rhombus. Where is my error?

• Magoosh Test Prep Expert July 6, 2017 at 7:49 am #

You don’t have an error per se in your immediate calculations, Sindhu. You’re correct that if we know for a fact that the quadrilateral is a rhombus, and we can see the angles of the rhombus, (B) is sufficient. However, you’ve made a mistake on a broader level– you’ve forgotten that we don’t actually know if the shape is a rhombus!

You can see a good breakdown of this in the first two minutes of the answer explanation video for this GRE Quant question. Basically, A and B are both insufficient for the same reason.

8. Aakriti October 4, 2016 at 10:41 am #

1 – B
2 – A, D
3 – 0.25
4 – B
5 – C

9. Chibuikem Okoro October 4, 2015 at 10:36 pm #

The only question I was stuck on beyond 2 mins was the first as I thought assigning the two different variable s and t meant they were different values (different prime numbers). I thought this was the case in gre where variables of different letters have different values?

10. Bhavik August 23, 2015 at 2:59 pm #

Hi Chris,

Won’t the answer of question 1 depend on the choice of numbers,

Take x = 3, y = 27 => x^3*y^3 = 3^12 , hence v= 3^6

So there are 6 factors except 1 in this case. Similarly, y can be 3^(3k) and v can attain higher values.
The no. of factors would be different in each case.

• Bhavik August 23, 2015 at 3:01 pm #

Reread it. The numbers are both primes. So it won’t work. 🙂

11. Nina June 4, 2015 at 8:36 am #

Hi Chris,

I heard that you need to answer all quant questions correctly in under 30 minutes instead of the 35 minutes in order to get a 170. Is that true?

Thank you!

Best,
Nina

• Chris Lele June 5, 2015 at 2:24 pm #

Nina,

That is a very interesting question. I’m curious as to where you heard that.

I’ve actually never heard any such thing, but it might actually be true. I hear this because apparently people have answered every question in quant correctly but not received a perfect score. The thinking is that it is difficulty of questions within that specific batch of questions that determine the ceiling. Or so the thinking goes.

Well, let me know where you heard that rumor. I really do want to find out if there is any truth behind it 🙂

• Nina June 5, 2015 at 2:51 pm #

Hi Chris,

thanks for the reply. I’ve read it on various forums on the internet. I actually just emailed ETS and will comment here if they get back to me. If this was really the case, it seems like it would make more sense to do the paper-based (non-adaptive and without such time constraints) to make a 170 most likely, right? Assuming someone had the choice between the PBT and CBT.

Best,
Nina

• Chris Lele June 5, 2015 at 4:51 pm #

Nina,

Thanks for the quick reply! I’ll have to do some snooping around the forums on my own. Looking forward to seeing what ETS has to say on the issue. Thanks for keeping us posted 🙂

• Nina June 6, 2015 at 8:43 pm #

Hi Chris,

they say its only the number of questions answered correctly that counts – with possible differences arising due to question difficulty (which seems really unfair to me).

Nina

• Chris Lele June 8, 2015 at 3:00 pm #

Well thanks to getting to the bottom of that.

And I agree with the question difficulty thing — totally unfair 🙁

12. rahman January 20, 2015 at 11:03 pm #

1 d
2 a,d
3 0.25
4 b
5 b

• Bilal August 13, 2016 at 4:28 am #

13. nehal November 6, 2014 at 4:38 pm #

thanks to GMAT quant I got 4 out of 5 in 9 mins

• Chris Lele May 4, 2015 at 5:24 pm #

Yes, working with GMAT quant makes these questions a lot easier!

Congrats on an impressive performance!

14. Mandeep March 18, 2014 at 10:23 am #

Hi Chris,

I don’t find any solution for Question # 3.

Can you please either add a video or provide a solution in a reply to my post?

………

BR
Mandeep

• Sonamata May 15, 2014 at 10:57 am #

You can find the explanation here: http://gre.magoosh.com/answers/22698583?&prompt_id=2192#text_explanation

• Rachel May 16, 2014 at 10:14 am #

Thanks for posting that Sonamata! 🙂

15. Daniel December 13, 2013 at 7:45 pm #

I was wondering something about question #2 (like everyone else). I know trig is not required in the GRE, but regardless, wouldn’t you be able to determine the area in choice B knowing it’s two isosceles triangles?

From that given information, you know that the parallelogram that results has side ratios of sqrt(2)x + sqrt(2)x + 1x + 1x, since the sides of a right isosceles triangle are in sqrt(2) :1:1 ratio. You can then use algebra to calculate out the size of the edges by finding x: sqrt(2)x + sqrt(2)x + x + x = 16. From there you can find the height of the parallelogram, and thus you can find the area, which is base*height.

Technically, you CAN find the area with enough work, correct? Thanks for this little quiz, though, it’s nice brushing up on my quantitative.

• Chris Lele December 16, 2013 at 11:39 am #

Hi Daniel,

So (2) is really tricky!

See, you can arrange two isosceles right triangles into a quadrilateral by arranging them into a rhombus. If you do so, you’ll find a rhombus with a perimeter of 16 only has an area of 8, not 16, the way a square with a perimeter of 16 does.

In general, almost all of the questions on the GRE will be easier than this one. There will only be one or two (in my humble opinion :)) that will be comparable in difficulty.

Hope that helps!

• Sriram July 10, 2014 at 7:23 pm #

If you arrange two isosceles right triangles side by side, you would get a parallelogram – not a rhombus. The hypotenuse of the two right triangles would be two sides of the quadrilateral and hence longer than the other two sides. So all four sides will not be of equal length.

As Daniel suggests, if the isosceles triangle have the equal sides to be of length x units, then the perimeter of the quadrilateral formed would be 2x(1 + sqrt(2)).

From the above information, the value of x can be determined as 8 ( sqrt(2) – 1) and the area computed to be x^2 = 10.98.

But the essence of the matter is that we still can’t one single answer for the area, therefore option B must be wrong!

• Chris Lele July 11, 2014 at 1:28 pm #

Wow, you are right! I can’t believe no one has caught that after all these years (myself included!). Yes, it’s definitely a parallelogram. And I’ll definitely have to change this question!

Thanks again, Sriram, for your valuable input!

• Sohaib May 4, 2015 at 11:54 am #

I guess it can form a square as well if you just superimpose the hypotenuse. In which case all sides wud be equal and each angle 90.

• Meghana July 11, 2016 at 5:30 am #

I’m confused.. So this means that with what the current question is, B is wrong because even though you can calculate the area, we get two possible values for it. So since the question asks whether you can determine the area or not, the answer is ‘no’ because there are two possible values for it.

• Magoosh Test Prep Expert July 13, 2016 at 12:41 pm #

Sounds like you’re not so confused after all— you are exactly right that (B) can’t be the right answer, because there is more than one possible value for the area of the choice. You want to only select answer choices that lead to one specific result, with no other results being possible.

16. Kai November 7, 2013 at 10:12 am #

For question #2, Since you know the angle and the length of any one side, can’t you use trig to find the area?

• Chris Lele November 7, 2013 at 10:58 am #

Hi Kai,

First off, the test wouldn’t require trig., beyond knowing your 30:60:90 ratios. With question #2, you don’t necessarily know the length of any one side, given the perimeter and the measurement of the angles. A rhombus could have the same angles and perimeter as very long parallelogram–but a very different area.

Hope that helps!

17. TT July 4, 2013 at 6:05 am #

Thanks,

TT

• Chris Lele July 5, 2013 at 1:43 pm #

Hmmm…that is a good question! I didn’t even notice that they had disappeared. I’m going to find out what happened, and I will get back to you :)!

• Eric B July 15, 2013 at 10:39 am #

• Margarette July 15, 2013 at 10:59 am #

Hi, Eric

They should be back in now! 🙂 Let me know if you have any trouble watching the videos on YouTube!

Best,
Margarette

• Eric B July 15, 2013 at 5:44 pm #

Thanks! 🙂

• rahman January 20, 2015 at 11:13 pm #

• Rachel January 21, 2015 at 10:38 am #

Hey Rahman,

You can find the answers in the video explanations at the bottom of the post. 🙂

18. Lena April 5, 2013 at 1:26 am #

Which is the best GRE Prep material out there that provides practice questions with the level of difficulty of these 5 questions?

• Chris Lele April 5, 2013 at 1:31 pm #

Hi Lena,

I’d say there are only a few out there, besides Magoosh.

Manhattan GRE
Nova’s
GMATprep (Official Guide and GMATprep test)

Hope that helps!

19. vignesh August 5, 2012 at 4:02 am #

rhombus is also one type of quadrilateral , then why should u neglect option A in second question

• Chris August 6, 2012 at 2:57 pm #

Let’s say you have a square with sides 4. Thus you have an area of 16. Now let’s say you have a rhombus with sides 4 but with two angles equal to 150 degrees each and the other two angles equal to 30 degrees each. Notice how this “squashed figure” would have a much smaller area than 14. Thus, (A) is not sufficient to answer the question.

Hope that helps!

20. Heath July 12, 2012 at 10:19 am #

did you mean to write by 75%*

21. Heath July 12, 2012 at 10:18 am #

Hi Chris,

It says decrease the area by 25%, but you appear to be decreasing the area by 75%. Did you mean to write to 75% in the question?

Thanks!

(P.S. I’m watching this without sound so forgive me if i missed something vital)

• Chris August 6, 2012 at 3:17 pm #

Great catch! Thanks for noticing that :). It should be decreased by 75%.

22. Julia Campos April 9, 2012 at 2:33 pm #

I did not get any. I do not understand them. Do not know how to solve them. An explanation for all would be very helpful.

Thanks.

Julia

• Chris April 9, 2012 at 3:02 pm #

No problem, I will provide a video explanation. Coming very soon :).

23. Jia April 9, 2012 at 12:36 am #

Plz put up the explanations for all the questions. I got Q1 & Q2 wrong!

• Chris April 9, 2012 at 3:02 pm #

Okay, I will put up explanations for all of the questions :).

24. Julia Campos April 6, 2012 at 2:58 am #

Are you going to post the video explanations?
Thanks.
Julia

• Chris April 6, 2012 at 9:53 am #

Hi Julia,

Next week I will post the video explanation for #2, as that is the question everybody seems to be missing.

25. Anshul April 4, 2012 at 10:01 am #

1) B
2) B, D
3) 0.25
4) E
5) C

🙂
It took me more time than it should have.

• Chris April 4, 2012 at 2:25 pm #

Anshul,

You answered most of them correctly :), except #2, which most people are missing. Take a look at answer choice (B) again.

26. James Brown April 3, 2012 at 11:24 am #

On #4 I was able to get an answer of E,

because 14, 15, 16, 17 when added together =62

and then I used negative integers

-14,-15,-16,-17=-62

then I added the two sums and came up with 0 which wasn’t listed, so I chose E….I know my answer is right, but is my logic correct in how I got to that answer?

• Chris April 3, 2012 at 5:44 pm #

Yep your logic is correct, but there is an even faster way:

If you know that each solution for x has a positive and a negative answer (14, -14, 15…etc, then each will cancel out so you don’t have to worry about adding up all the positive integers than subtracting the sum of the negative ones).

Hope that helps :).

27. Jayant April 3, 2012 at 7:14 am #

got my mistake

• Chris April 3, 2012 at 11:09 am #

No problem 🙂

28. Jayant April 3, 2012 at 7:08 am #

Shouldnt the answer to the second question be B and D? since b gives us all the angles and a square is formed and a quadrilateral can only be formed if we join them with a common hypotenuse ( equal in length).

29. Praveen April 2, 2012 at 10:40 pm #

1)B (s,t=2 and v=8)
2) B,C,D (I am not sure about option C)
3) 0.25 ( solve for 0.5 * k * 2*sq(k) = 1/8)
4)D (because k includes negative values as well, adding up to zero)
5) 60000 divisors each
for 350,000 divisors = 5 * 6 * 2 ( 350,000 = 2^4 * 5^5 * 7)
for 45,000 divisors = 5 * 3 * 4 (45,000 = 2^3 * 3^2 * 5^4)
I took 13 minutes but 🙁

• Chris April 3, 2012 at 11:12 am #

Hi Praveen,

All of those are correct, except for #2, which seems to be stumping everyone :).

My clue for that question is try to think of two different shapes that can result from each condition. Just because you can think of one condition doesn’t mean that is the only condition. (Hint: a square + rhombus; rhombus + parallelogram).

Hope that helps 🙂

30. Pemdas@BTG April 2, 2012 at 12:33 pm #

Let me retype Questions ## 4 and 5 as something went wrong in text after I posted

14,-14,15,-15,16,-16
Sum=0

Question #5) 350,000=5*7*(2*5)^4=5^5 *2^4 *7, (5+1)(4+1)(1+1)=60
45,000=3^2 *5 *(2*5)^3=2^3 *3^2 *5^4, (3+1)(2+1)(4+1)=60

• Chris April 2, 2012 at 2:08 pm #

Hi Pemdas,

If the quadrilateral is a rhombus, then it will have a different area than if it was a square.

We have the exact dimensions of quadrilateral: width = .6x, length = x, (x)(.6x) = 16. Solving for ‘x’ gives us only one positive value.

• Pemdas@BTG April 2, 2012 at 2:29 pm #

right, the area of rhombus is always less than the area of square. In our case if the quadrilateral is a square we get max.area=(16/4)^2=16, and if we have rhombus the area will be always less than 16. How I could miss it 🙁

• Chris April 2, 2012 at 9:52 pm #

Maybe I’ll make this a monthly challenge, so you’ll have another chance to get 5/5. Still, 4/5 is very good :).

31. Pemdas@BTG April 2, 2012 at 12:26 pm #

Question #5) was merged with Question #4) 🙂

32. Pemdas@BTG April 2, 2012 at 12:23 pm #

the whole task took me 9 mins

33. Pemdas@BTG April 2, 2012 at 12:23 pm #

Question #1) when two primes factorized and raised to the power of 3 is perfect square the only viable case which comes to my mind is s=t=2 and (st)^3=(2*2)^3=64 or 8^2. Hence v=8 and 8=2^3 or (3+1) factors with 1 and 3 factors greater than 1.

Question #2) I mark answers A and D

Question #3) answer 0.25, this one I knew answer ans solved earlier as have premium Magoosh account

Question #4) answer E, 13^2<x^2 (5+1)(4+1)(1+1)=60
45,000=3^2 *5*(2*5)^3=2^3 *3^2 *5^4, factors number –> (3+1)(2+1)(4+1)=60

34. Vanan April 2, 2012 at 10:57 am #

1. A)
2. C), E)
3. 0.707
4. B)
5. A)

• Chris April 2, 2012 at 9:51 pm #

Hi Vanan,

As the post mentioned, these are some tough questions :).

Give it another shot, and see if you can get them right.

Magoosh blog comment policy: To create the best experience for our readers, we will only approve comments that are relevant to the article, general enough to be helpful to other students, concise, and well-written! 😄 Due to the high volume of comments across all of our blogs, we cannot promise that all comments will receive responses from our instructors.

We highly encourage students to help each other out and respond to other students' comments if you can!

If you are a Premium Magoosh student and would like more personalized service from our instructors, you can use the Help tab on the Magoosh dashboard. Thanks!