In my experience, students often hit a roadblock when they see the word *asymptote*. What is an asymptote anyway? How do you find them? Is this going to be on the test??? (The answer to the last question is *yes*. Asymptotes definitely show up on the AP Calculus exams).

Of the three varieties of asymptote — horizontal, vertical, and oblique — perhaps the oblique asymptotes are the most mysterious. In this article we define oblique asymptotes and show how to find them.

## What is an Oblique Asymptote?

An **oblique** (or **slant**) **asymptote** is a slanted line that the function approaches as *x* approaches ∞ (*infinity*) or -∞ (*minus infinity*). Let’s explore this definition a little more, shall we?

### It’s All About the Line

Since all non-vertical lines can be written in the form *y* = *mx* + *b* for some constants *m* and *b*, we say that a function *f*(*x*) has an oblique asymptote *y* = *mx* + *b* if the values (the *y*-coordinates) of *f*(*x*) get closer and closer to the values of *mx* + *b* as you trace the curve to the right (*x* → ∞) or to the left (*x* → -∞), in other words, if there is a good **approximation**,

*f*(*x*) ≈ *mx* + *b*,

when *x* gets extremely large in the positive or negative sense.

Still with me? I understand completely if you’re still a little lost, but let’s see if we can clear up some confusion using the graph shown below.

As you can see, the function (shown in blue) seems to get closer to the dashed line. Therefore, the oblique asymptote for this function is *y* = ½ *x* – 1.

## Finding Oblique Aymptotes

A function can have at most two oblique asymptotes, but only certain kinds of functions are expected to have an oblique asymptote at all. For instance, *polynomials* of degree 2 or higher do not have asymptotes of any kind. (Remember, the **degree** of a polynomial is the highest exponent on any term. For example, 10*x*^{3} – 3*x*^{4} + 3*x* – 12 has degree 4.)

As a quick application of this rule, you can say for sure *without any work* that there are no oblique asymptotes for the quadratic function *f*(*x*) = *x*^{2} + 3*x* – 10, because it’s a polynomial of degree 2.

On the other hand, some kinds of *rational functions* do have oblique asymptotes.

### Rational Functions

A **rational function** has the form of a fraction, *f*(*x*) = *p*(*x*) / *q*(*x*), in which both *p*(*x*) and *q*(*x*) are polynomials. If the degree of the numerator (top) is exactly one greater than the degree of the denominator (bottom), then *f*(*x*) will have an oblique asymptote.

So there are no oblique asymptotes for the rational function, .

But a rational function like does have one. Knowing when there is a horizontal asymptote is just half the battle. Now how do we find it? This next step involves *polynomial division*.

### Polynomial Division to Find Oblique Asymptotes

If you’ve made it this far, you probably have seen long division of polynomials, or synthetic division, but if you are rusty on the technique, then check out this video or this article.

The idea is that when you do polynomial division on a rational function that has one higher degree on top than on the bottom, the result always has the form *mx* + *b* + *remainder term*. Then the oblique asymptote is the linear part, *y* = *mx* + *b*. We don’t need to worry about the remainder term at all.

#### Example Using Polynomial Division

Let’s see how the technique can be used to find the oblique asymptote of .

The long division is shown below.

Because the quotient is 2*x* + 1, the rational function has an oblique asymptote:

*y* = 2*x* + 1.

### Hyperbolas

Another place where oblique asymptotes show up is in the graphs of *hyperbolas*. Remember, in the simplest case, a **hyperbola** is characterized by the standard equation,

The hyperbola graph corresponding to this equation has exactly two oblique asymptotes,

The two asymptotes cross each other like a big X.

#### Example Involving a Hyperbola

Let’s find the oblique asymptotes for the hyperbola with equation *x*^{2}/9 – *y*^{2}/4 = 1.

In the given equation, we have *a*^{2} = 9, so *a* = 3, and *b*^{2} = 4, so *b* = 2. This means that the two oblique asymptotes must be at *y* = ±(*b*/*a*)*x* = ±(2/3)*x*.

### More General Hyperbolas

It’s important to realize that hyperbolas come in more than one flavor. If the hyperbola has its terms switched, so that the “*y*” term is positive and “*x*” term is negative, then the asymptotes take a slightly different form. Furthermore, if the center of the hyperbola is at a different point than the origin, (*h*, *k*), then that affects the asymptotes as well. Below is a summary of the various possibilities.

## Final Thoughts

So when you see a question on the AP Calculus AB exam asking about oblique asymptotes, don’t forget:

- If the function is rational, and if the degree on the top is one more than the degree on the bottom: Use polynomial division.
- If the graph is a hyperbola with equation
*x*^{2}/*a*^{2}–*y*^{2}/*b*^{2}= 1, then your asymptotes will be*y*= ±(*b*/*a*)*x*. Other kinds of hyperbolas also have standard formulas defining their asymptotes.

Keeping these techniques in mind, oblique asymptotes will start to seem much less mysterious on the AP exam!

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##### About Shaun Ault

Shaun earned his Ph. D. in mathematics from The Ohio State University in 2008 (Go Bucks!!). He received his BA in Mathematics with a minor in computer science from Oberlin College in 2002. In addition, Shaun earned a B. Mus. from the Oberlin Conservatory in the same year, with a major in music composition. Shaun still loves music -- almost as much as math! -- and he (thinks he) can play piano, guitar, and bass. Shaun has taught and tutored students in mathematics for about a decade, and hopes his experience can help you to succeed!

### 2 Responses to “How do you find the Oblique Asymptotes of a Function?”

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**Magoosh blog comment policy:** To create the best experience for our readers, we will approve and respond to comments that are relevant to the article, general enough to be helpful to other students, concise, and well-written! :) If your comment was not approved, it likely did not adhere to these guidelines. If you are a Premium Magoosh student and would like more personalized service, you can use the Help tab on the Magoosh dashboard. Thanks!

Hi Shaun:

I’m mathematically “challenged” but have been tutored by a cousin of mine who recently received a Phd in physics, of all things.

Anyways, your site has been very helpful to me as you make everything easy to follow and understand. Thanks. elliot

Glad to hear, Elliot. 😀

Best of luck.