GMAT Circles: An Introduction

Hand holding GMAT circle

Are you prepping for GMAT geometry questions? Feeling confused or in need of a refresher on circles? Read on to get a rundown of GMAT circles terminology, concepts, and practice questions.


Table of Contents


GMAT Circles: Basic Terminology

A circle is the set of all points equidistant from a fixed point.  That means a circle is this:

GMAT circle

and not this:

Incorrect Circle-Cliparts

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In other words, the circle is only the curved round edge, not the middle filled-in part.  A point on the edge is “on the circle”, but a point in the middle part is “in the circle” or “inside the circle.”  In the diagram below,

Points on GMAT Circle

point A is on the circle, but point B is in the circle.

By far, the most important point in the circle is the center of the circle, the point equidistance from all points on the circle.

Equidistant Circle Points GMAT

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Any line segment that has both endpoints on the circle is a chord.

GMAT Circle Chord

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By the way, the word “chord” in this geometric sense is actually related to “chord” in the musical sense: the link goes back to Mr. Pythagoras (c. 570 – c. 495 BCE), who was fascinated with the mathematics of musical harmony.

If the chord passes through the center, this chord is called a diameter.  The diameter is a chord.  A diameter is the longest possible chord.  A diameter is the only chord that includes the center of the circle.

GMAT Circle Diameter

The diameter is an important length associated with a circle, because it tells you the maximum length across the circle in any direction.

An even more important length is the radius.  A radius is any line segment with one endpoint at the center and the other on the circle.

GMAT Circle Radius

As is probably clear visually, the radius is exactly half the diameter, because a diameter can be divided into two radii.  The radius is crucially important, because if you know the radius, it’s easy to calculate not only the diameter, but also the other two important quantities associated with a circle: the circumference and the diameter.

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Circle Formulas

The circumference is the length of the circle itself.  This is a curve, so you would have to imagine cutting the circle and laying it flat against a ruler.  As it turns out, there is a magical constant that relates the diameter (d) & radius (r) to the circumference.  Of course, that magical constant is pi.  From the very definition of pi itself, here are two equations for the circumference, c.

c = {pi}d

c = 2{pi}r

If you remember the second, more common form, you don’t need to know the first.  The number pi is slightly larger than 3 — this means that three pieces of string, each as long as the diameter, together would not be quite long enough to make it all the way around the circle.  The number pi can be approximated by 3.14 or by the fraction 22/7.  Technically, it is an irrational number that goes on forever in a non-repeating pattern.

These two formulas follow from the definition of pi, so basically every culture on earth figured out these.  By contrast, the area of circle was discovered by one brilliant mathematician, and everyone on earth has this one man to thank for his formula for the area of a circle.  That man was Archimedes (c. 287 – c. 212 BCE).  Here is Archimedes’ amazing formula:

A = {pi}{r^2}

  • This is a GMAT circle formula you need to know cold on test day.

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Circles and Angles

Suppose you stand at the center of a circle and turn around that you face each and every point on the circle.  You would turn all the way around, which is an angle of 360º.  In this sense, a whole circle has an angle of 360º.  If you divided a circle equally, you could calculate the angle of each “slice”.  Here are a few division results that could help you to know on test day (I’m just giving the ones that come out as nice round numbers, not the ones that result in ugly decimals):

360/2 = 180

360/3 = 120

360/4 = 90

360/5 = 72

360/6 = 60

360/8 = 45

360/9 = 40

360/10 = 36

360/12 = 30

Arcs and Arclength

Suppose we look at a “slice” of a circle, like a slice of pizza.

Circles and Angles-Magoosh

The curved line from A to B, a part of the circle itself, is called an arc.  This corresponds to the crust of the pizza.

We can talk about the size of an arc in one of two ways: (a) its angle, sometimes called “arc angle” or “arc measure“, and (b), its length, called arclength.  The angle of the arc, its arc measure, is just the same as the angle at the center of the circle.  Here ∠AOB = 60°, so the measure of arc AB is 60°.

We find the arclength by setting up a proportion of part-to-whole.  The angle is part of the whole angle of a circle, 360°.  The arclength is part of the length all the way around, i.e. the circumference.  Therefore:

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Here, let’s say the radius is r = 12.  Then, the circumference is c = 24{pi}.  Since the angle is 60°, the ratio on the left side, angle/360, becomes 1/6.  Call the arclength x.

{1/6} = {x/{24{pi}}}


{24{pi}} = 6x

{4{pi}} = x = arclength.

In other words, since the angle 60° is one sixth of the full angle of a circle, the arclength is one sixth of the circumference.

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GMAT Circles Practice Questions

  1. In the shaded region above, ∠KOL = 120°, and the area of the entire circle is A = 144{pi}.  The perimeter of the shaded region is
    1. 12 + 8{pi}
    2. 12 + 16{pi}
    3. 24 + 8{pi}
    4. 24 + 16{pi}
    5. 24 + 24{pi}
Show answer and explanation

1) The area 144{pi} = {{pi}r^2}, so r = 12.  This means KO = 12 and OL = 12, so those two sides together are 24.  The remaining side is arc KL.  The whole circumference is c = 2{pi}r = 24{pi}.  The angle of 120° is 1/3 of a circle, so the arclength is 1/3 of the circumference.  This means, arclength = 8{pi}, and therefore the entire perimeter is 24 + 8{pi}.  Answer = C.


  1. Given that a “12-inch pizza” means circular pizza with a diameter of 12 inches, changing from an 8-inch pizza to a 12-inch pizza gives you approximately what percent increase in the total amount of pizza?
    1. 33
    2. 50
    3. 67
    4. 80
    5. 125
Show answer and explanation

The 8-inch pizza has a radius of r = 4, so the area is A = 16{pi}. That area is how much pizza you get. The 12-inch pizza has a radius of r = 6 and an area of A = 36{pi}. When you change from 16 to 36, what is the percentage change? Well, that’s more than double, so it must be a percent greater than 100%. The only answer choice greater than 100% is answer E.


  1. What is the diameter of circle Q?
    • Statement #1 — the circumference of Q is c = 12{pi}.
    • Statement #2 — the area of Q is A = 36{pi}.


Show answer and explanation

Statement #1: if you know the circumference, then you can use c = 2{pi}r to solve for the radius, or c = {pi}d to solve for the diameter. Either way, you can find the diameter, so this statement by itself is sufficient.

Statement #2: if you know the area, you can find the radius, and then double that to get the diameter. This statement by itself is also sufficient.

Both statements alone are sufficient. Answer = D.

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10 Responses to GMAT Circles: An Introduction

  1. Daniel December 2, 2020 at 12:55 am #

    Very helpful. Every time I’ve asked a question during your course, it’s been answered quickly while explaining the concept, not just the formula. I’m using another course right now, and I can say they are not nearly as helpful with my questions.

  2. DropBear September 5, 2015 at 12:55 pm #

    Hi Mike,

    Just wondering, is there any useful formulas for chords? for example you have a circle, and there is a chord equal to the radius (so for visualization purposes this could make an equilateral triangle with two other radii). Is there a formula or method to calculate the area between the chord and the smaller arc of the circle?

    • DropBear September 5, 2015 at 1:41 pm #

      Wait… I think I solved my own question. the area I am talking about is basically the difference between the area of a 60 degree arc and an equilateral triangle…

      area of 60 deg arc = (pi*r^2/6)
      Area of equilateral triangle of side r = (sqrt(3)/4)*r
      —> area between radius sized cord and outside of circle = (pi*r^2/6) – (sqrt(3)/4)*r = (2*pi*r^2 – 3r)/12

      Please let me know if I have gone about this the right way. Still not sure if this is correct.

      • Mike MᶜGarry
        Mike McGarry September 8, 2015 at 12:40 pm #

        Dear DropBear,
        I’m happy to respond. 🙂 Notice that, in the formula for the area of an equilateral triangle, as in any area formula, we need a factor of length squared. Here, the r needs to be squared. Also, you seem to have lost the radical 3 in the final formula.
        Here’s what I am going to say. Even if you had gotten the perfect formula, that formula is virtually useless. Unless the GMAT happens to ask about that very specific case, this result is useless. What is incredibly valuable is your ability to think through situations such as this. Forget the final result formulas, which are useless, but value your ability to think through unique mathematical situations.
        Does this distinction make sense?
        Mike 🙂

  3. Serena August 20, 2013 at 6:55 pm #

    Shouldn’t c= 2*pi*r instead of c= 2*pi*d in above?

    • Mike MᶜGarry
      Mike August 21, 2013 at 1:49 pm #

      YES! ABSOLUTELY CORRECT! Yes, that was a typo, and I just corrected it. Thank you very much for pointing this mistake out. Best of luck to you, my friend.
      Mike 🙂

  4. Peter June 23, 2013 at 9:01 pm #

    I am wondering why answer to Question 1 is not choice B(50)

    This is how I was calculating:-

    If original diameter was 8, then increase in diameter is by 4 (8 inch changed to 12 inch)
    This means if original diameter was 100 then increase in diameter would be by amount of (100*4)/8=50

    Hence % increase is 50%

    Could you please let me know where am I thinking wrong?


    • Mike MᶜGarry
      Mike June 24, 2013 at 9:53 am #

      You fell into the classic GMAT pizza-math trap. The numbers 8 & 12 are diameters — they’re lengths. By contrast, “amount of pizza”, how much you can eat, is AREA, not length. That’s why we need to figure out the areas corresponding to d = 8 and d = 12, and base the percents on those areas.
      Mike 🙂

      • Peter June 24, 2013 at 8:21 pm #

        Oh I see…:-)
        Thanks Mike. Appreciate you reply.

        • Mike MᶜGarry
          Mike June 25, 2013 at 9:54 am #

          You are more than welcome, my friend. Best of luck to you!
          Mike 🙂

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