Exponents can be tricky, but even more so when they are negative or fractional. This article begins by reviewing the basic laws of exponents (powers). Then we’ll tackle plenty of practice problems involving negative exponents and fractional exponents.

_{Image by Comfreak}

## How Do Exponents Work?

In their simplest form, exponents stand for repeated multiplication. The smallish number (the **exponent**, or **power**) located to the upper right of main number (the **base**) tells how many times to use the base as a factor.

- 3
^{2}= 3 × 3 = 9 - 2
^{5}= 2 × 2 × 2 × 2 × 2 = 32 - It also works for variables:
*x*^{3}= (*x*)(*x*)(*x*)

You can even have a power of 1. That just means a single factor of the base: *x*^{1} = *x*.

But what sense can we make out of expressions like 4^{-3}, 25^{3/2}, or *y*^{-1/6}? What does it mean to take “-3” factors of a number? Or “3/2” or “-1/6” of a factor?

It all begins with the **Laws of Exponents** (Check out: Quick Tips on Using the Exponent Rules.)

### The Laws of Exponents

- Multiplication Law (same bases):
*x*^{a}*x*=^{b}*x*^{a+b} - Division Law (same bases):
*x*/^{a}*x*=^{b}*x*^{a-b} - Power Law: (
*x*)^{a}=^{b}*x*^{ab} - Multiplication Law (same powers):
*x*^{a}*y*= (^{a}*xy*)^{a} - Division Law (same powers):
*x*/^{a}*y*= (^{a}*x*/*y*)^{a}

Now if we’re going to try to make sense of negative and fractional exponents, then we must at least make sure that our definitions will stay consistent with these Laws of Exponents.

For example, you may already know that the zero exponent on any base results in the number 1 (with one exception: 0^{0} is undefined).

Let’s see if the rule *x*^{0} = 1 is consistent with the Laws of Exponents.

- If
*x*^{0}= 1, then*x*^{0}*x*= 1^{b}*x*=^{b}*x*. That’s consistent with the Multiplication Law:^{b}*x*^{0}*x*=^{b}*x*^{0+b}=*x*^{b} - By the Division Law, if the two exponents happen to be the same, then
*x*/^{a}*x*=^{a}*x*=^{a-a}*x*^{0}= 1. This certainly agrees with the algebraic fact that dividing a quantity by itself yields 1.

In fact, all of the Laws are consistent with the rule *x*^{0} = 1.

## Negative Exponents

Consider the Division Law with *a* = 0.

*x*^{0}/*x ^{b}* =

*x*=

^{0-b}*x*

^{-b}But remember: *x*^{0} = 1. So, reading the above equation backwards, we have discovered the rule for negative exponents!

**Negative exponents translate to fractions.**

For example, 4^{-3} = 1/(4^{3}) = 1/64.

The more negative the exponent, the *smaller* the value. This is especially important in the sciences when talking about orders of magnitude (how big or small things are). In fact, the positive and negative powers of 10 are essential in **scientific notation**.

- (giga-) 10
^{9}= 1,000,000,000 = 1 billion - (mega-) 10
^{6}= 1,000,000 = 1 million - (kilo-) 10
^{3}= 1000 = 1 thousand - (Unit – no prefix) 10
^{0}= 1 - (milli-) 10
^{-3}= 0.001 = 1 thousandth - (micro-) 10
^{-6}= 0.000 001 = 1 millionth - (nano-) 10
^{-9}= 0.000 000 001 = 1 billionth

## Fractional Exponents

How can we define fractional exponents so that the Laws of Exponents remain consistent?

Consider any fraction, say 1/2. If you multiply by the denominator, you end up back at the value 1.

(1/2)(2) = 1

Now consider 1/2 and 2 as exponents on a base. For example, with base = 9, we could write:

9^{(1/2)(2)} = 9^{1}

The right side is simply equal to 9. But the left side can be rewritten using the Power Law.

(9^{1/2})^{2} = 9

So, whatever 9^{1/2} is, its square must equal 9. In other words, 9^{1/2} is the *square root* of 9, that is, 9^{1/2} = 3.

In general, *x*^{1/2} is the square root of *x*.

What’s more, is that it works the same way with fractional exponents of the form 1/*n* for any number *n*.

*Fractional exponents translate to roots.*

### More About Fractional Exponents

So far, we have rules for exponents like 1/2, 1/3, 1/10, etc. But what about 2/3, 9/4, -11/14, etc.? Again, our Laws of Exponents come to the rescue!

For instance, if you need to know the value of 8^{2/3}, then first write 2/3 as a product.

8^{2/3} = 8^{(1/3)(2)} = (8^{1/3})^{2}

Then, work out 8^{1/3}, which is by definition the cube root of 8. Since we know that 2^{3} = 8, we have 8^{1/3} = 2.

8^{2/3} = (8^{1/3})^{2} = (2)^{2} = 4

In general, you can always express a fractional exponent in terms of roots and powers.

You may even have to deal with negative fractional exponents. Just think of what each property tells you: Negative exponents translate to fractions, and fractional exponents translate to roots (and powers).

## Practice Problems

Now are you ready for some practice?

^{By Agenturfotografin}

For each problem below, simplify as much as possible. If the expression has a variable, be sure that your final result has only positive whole exponents. Answers are given at the end.

- 125
^{4/3} - 6
^{-2} - 16
^{-1/4} *a*^{-1}- (4
*x*)^{0} - 4
*x*^{0} - (
*x*^{2})^{-8/3} - (
*z*^{2}+ 25)^{1/2} - (1000p
^{6})^{-1/3} - (
*x*^{1/2}+*y*^{1/2})^{2}

### Solutions

**625**.**1/36**. 6^{-2}= 1/6^{2}= 1/36.**1/2**.

**1/**. (The power -1 produces the*a***reciprocal**of the base.)**1**. Anything to the zero power gives the value 1 (as long as the base is nonzero, which we tend to assume in problems like this).**4**. Be careful of your*order of operations*. The zero exponent only applies to*x*, not the factor of 4 in front of it.- Use the Laws of Exponents to simplify.

- .

Yes, this is the final answer! Be careful when working with powers and radicals.So, the answer is**You can never break apart a power or radical over a plus or minus!****NOT**equivalent to*z*+ 5. - Laws of Exponents to the rescue again!

- Just as in Problem 8, you can’t just break up the expression into two terms. In other words, resist the urge to write down
*x*+*y*as your final answer. I guarantee that you’ll see a big red mark through that result if you do it on the next test.Instead, think

*algebraically*. Square the binomial first and then rewrite your exponents. (Remember, (*a*+*b*)^{2}=*a*^{2}+ 2*ab*+*b*^{2}.)

Very clearly explained. The explanation equips the learner to think and understand the reason for using a certain method

Thank you Shaun! The way you explain makes things clear and easy to understand as well as to put into practice. Keep doing the good job of teaching and sharing. I enjoyed your approach a lot!