{"id":9205,"date":"2017-03-02T14:12:43","date_gmt":"2017-03-02T22:12:43","guid":{"rendered":"https:\/\/magoosh.com\/hs\/?p=9205"},"modified":"2017-03-03T18:14:29","modified_gmt":"2017-03-04T02:14:29","slug":"ap-calculus-review-product-rule","status":"publish","type":"post","link":"https:\/\/magoosh.com\/hs\/ap\/ap-calculus-review-product-rule\/","title":{"rendered":"AP Calculus Review: Product Rule"},"content":{"rendered":"<p>The product rule is just one of many essential <a href=\"https:\/\/magoosh.com\/hs\/ap\/calculus-review-derivative-rules\/\">derivative rules<\/a>.  Together with the Sum\/Difference Rule, Power Rule, Quotient Rule, and Chain Rule, these rules form the backbone of our methods for finding derivatives.  In this article I&#8217;ll explain what the Product Rule is and how to use it in typical problems on the AP Calculus exams.  <\/p>\n<h2>The Product Rule<\/h2>\n<p>Suppose <em>f<\/em> and <em>g<\/em> are differentiable functions.  Then the product function, <em>fg<\/em> is also differentiable, and<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/product_rule.gif\" alt=\"Product Rule\" width=\"275\" height=\"19\" class=\"aligncenter size-full wp-image-9206\" \/><\/p>\n<p>Here is another way to state the rule in a more compact way:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/product_rule2.gif\" alt=\"Product Rule written in terms of u and v\" width=\"130\" height=\"18\" class=\"aligncenter size-full wp-image-9207\" srcset=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/product_rule2.gif 130w, https:\/\/magoosh.com\/hs\/files\/2017\/02\/product_rule2-30x4.gif 30w\" sizes=\"(max-width: 130px) 100vw, 130px\" \/><\/p>\n<p>Many textbooks write the terms in different orders.  Here is yet another version of the rule, this time using <em>Leibniz notation<\/em>.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/product_rule3.gif\" alt=\"Product Rule in Leibniz notation\" width=\"161\" height=\"38\" class=\"aligncenter size-full wp-image-9215\" \/><\/p>\n<h3>Example 1<\/h3>\n<p>Find the derivative of <em>f<\/em>(<em>x<\/em>) = <em>x<\/em><sup>5<\/sup> sin <em>x<\/em>.<\/p>\n<p>This function is the product of two functions, <em>u<\/em> = <em>x<\/em><sup>5<\/sup> and <em>v<\/em> = sin <em>x<\/em>.  Using the Product Rule, <\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Example1.gif\" alt=\"Using the product rule.  Example 1.\" width=\"290\" height=\"60\" class=\"aligncenter size-full wp-image-9209\" \/><\/p>\n<p>Note, the correct derivative is <strong>not<\/strong> found by just taking the product of the derivatives.  In other words,  <em>f<\/em>&nbsp;&#039;(<em>x<\/em>) &ne; 5<em>x<\/em><sup>4<\/sup> cos <em>x<\/em>.<\/p>\n<h3>Example 2<\/h3>\n<p>In the next example, we&#8217;ll see that the Product Rule can even be used when very little information is known about the individual functions.<\/p>\n<p>Suppose <em>f<\/em> and <em>g<\/em> are differentiable at <em>x<\/em> = 4, and suppose we know that <em>f<\/em>(4) = -3, <em>g<\/em>(4) = 2, <em>f<\/em>&nbsp;&#039;(4) = 7, and <em>g<\/em>&nbsp;&#039;(4) = 3.  Let <em>h<\/em> = <em>fg<\/em>.  What is the value of <em>h<\/em>&nbsp;&#039;(4)?<\/p>\n<p><em>Be careful!<\/em>  The answer is <strong>not<\/strong> 21.  Instead, set up the rule and then plug in the known information:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Example2.gif\" alt=\"Product Rule example 2, worked out.\" width=\"334\" height=\"121\" class=\"aligncenter size-full wp-image-9210\" \/><\/p>\n<h2>Practice Problems<\/h2>\n<p>Now&#8217;s your chance to practice using the Product Rule!  Solutions are provided at the end.<\/p>\n<ol>\n<li>Find the derivative of <img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice1.gif\" alt=\"Practice Problem 1\" width=\"58\" height=\"17\" class=\"alignnone size-full wp-image-9211\" srcset=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice1.gif 58w, https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice1-30x9.gif 30w\" sizes=\"(max-width: 58px) 100vw, 58px\" \/>.<\/li>\n<li>If <em>y<\/em> = sec <em>x<\/em>, what is <em>y<\/em>&nbsp;&#039;&#039;?<\/li>\n<li><em>(Requires Chain Rule)<\/em> Differentiate <em>g<\/em>(<em>t<\/em>) = cos(<em>t<\/em> sin <em>t<\/em>).<\/li>\n<li>Find the equation of the tangent line to the curve <img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice4.gif\" alt=\"Practice Problem 4\" width=\"76\" height=\"19\" class=\"alignnone size-full wp-image-9216\" srcset=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice4.gif 76w, https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice4-30x8.gif 30w\" sizes=\"(max-width: 76px) 100vw, 76px\" \/> at <em>x<\/em> = 1.<\/li>\n<\/ol>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2016\/10\/animatedthinkingcap.gif\" alt=\"Thinking cap -Magoosh\" width=\"198\" height=\"290\" class=\"size-full wp-image-7999\" \/><\/p>\n<h3>Solutions<\/h3>\n<ol>\n<li><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice1_solution.gif\" alt=\"Solutions to Practice Problem 1\" width=\"437\" height=\"45\" class=\"alignnone size-full wp-image-9212\" \/><\/li>\n<li>The first derivative is: <em>y<\/em>&nbsp;&#039; = sec <em>x<\/em>  tan <em>x<\/em>.  The Product Rule is required to find the second derivative:\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice2_solution.gif\" alt=\"Solution to Practice Problem 2\" width=\"290\" height=\"95\" class=\"aligncenter size-full wp-image-9213\" \/><\/li>\n<li>Use the Chain Rule first, and then Product Rule for the derivative of the &#8220;inside&#8221; function.<br \/>\n<img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice3_solution.gif\" alt=\"Solution for Practice Problem 3\" width=\"316\" height=\"116\" class=\"aligncenter size-full wp-image-9214\" \/>\n<\/li>\n<li>To find the equation of the tangent line, we will need the slope.  And that requires finding a derivative.\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice4_solutionA.gif\" alt=\"Solution to Practice Problem 4, part A\" width=\"295\" height=\"38\" class=\"aligncenter size-full wp-image-9217\" \/><\/p>\n<p>Plug in <em>x<\/em> = 1 to find the slope.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice4_solutionB.gif\" alt=\"Finding the slope.\" width=\"340\" height=\"37\" class=\"aligncenter size-full wp-image-9218\" \/><\/p>\n<p>Finally, we need the <em>y<\/em>-coordinate of the point.  Plug <em>x<\/em> = 1 back into the original function to get: <em>y<\/em> = <em>e<\/em>.  Now we can put together the tangent line equation:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/02\/ProductRule_Practice4_solutionC.gif\" alt=\"Solution to Practice Problem 4 - tangent line equation\" width=\"177\" height=\"63\" class=\"aligncenter size-full wp-image-9219\" \/>\n<\/ol>\n","protected":false},"excerpt":{"rendered":"<p>The product rule is just one of many essential derivative rules. Together with the Sum\/Difference Rule, Power Rule, Quotient Rule, and Chain Rule, these rules form the backbone of our methods for finding derivatives. In this article I&#8217;ll explain what the Product Rule is and how to use it in typical problems on the AP [&hellip;]<\/p>\n","protected":false},"author":223,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[240],"tags":[241],"ppma_author":[24932],"class_list":["post-9205","post","type-post","status-publish","format-standard","hentry","category-ap","tag-ap-calculus"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v21.7 (Yoast SEO v21.7) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>AP Calculus Review: Product Rule - Magoosh Blog | High School<\/title>\n<meta name=\"description\" content=\"In this article I&#039;ll explain what the product rule is and how to use it in typical problems on the AP Calculus exams. 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