{"id":8788,"date":"2017-01-30T17:06:49","date_gmt":"2017-01-31T01:06:49","guid":{"rendered":"https:\/\/magoosh.com\/hs\/?p=8788"},"modified":"2018-10-24T03:40:09","modified_gmt":"2018-10-24T10:40:09","slug":"ap-calculus-exam-review-antidifferentiation","status":"publish","type":"post","link":"https:\/\/magoosh.com\/hs\/ap\/ap-calculus-exam-review-antidifferentiation\/","title":{"rendered":"AP Calculus Exam Review: Antidifferentiation"},"content":{"rendered":"<p>Antidifferentiation is an essential tool for evaluating integrals.  In fact, you might say that antidifferentiation is pretty much the same thing as finding an <a href=\"https:\/\/magoosh.com\/hs\/ap\/ap-calculus-review-indefinite-integrals\/\">indefinite integral<\/a>.<\/p>\n<p>When we antidifferentiate a function, we are simply finding another function whose derivative is equal to the one we started with.<\/p>\n<h2>What is Antidifferentiation?<\/h2>\n<p><strong>Antidifferentiation<\/strong> is the reverse of <strong>differentiation<\/strong>.  So just as differentiation is the process of finding a derivative, <em>anti<\/em>differentiation is the catch-all term for any formula, technique, or method of finding an <em>anti<\/em>derivative.<\/p>\n<p>If <em>f<\/em> is a function, then we say that <em>F<\/em> is an <strong>antiderivative<\/strong> for <em>f<\/em> if <em>F<\/em>&nbsp;&#039;(<em>x<\/em>) = <em>f<\/em>(<em>x<\/em>).<\/p>\n<h3>How Many Antiderivatives Can a Function Have?<\/h3>\n<p>If a function has one antiderivative, then it has <em>infinitely<\/em> many antiderivatives.  This is because the derivative of any constant is 0.  So if <em>F<\/em>(<em>x<\/em>) is an antiderivative of <em>f<\/em>(<em>x<\/em>) and <em>C<\/em> is any constant, then<\/p>\n<p>[<em>F<\/em>(<em>x<\/em>) + <em>C<\/em>]&#039; = <em>F<\/em>&nbsp;&#039;(<em>x<\/em>) + [C]&#039; = <em>f<\/em>(<em>x<\/em>) + 0 = <em>f<\/em>(<em>x<\/em>).<\/p>\n<p>Therefore, <em>F<\/em>(<em>x<\/em>) + <em>C<\/em> is <em>also<\/em> an antiderivative for <em>f<\/em>.  We call <em>C<\/em> the <strong>constant of integration<\/strong>.<\/p>\n<h3>Notation and Relationship to Integral<\/h3>\n<p>The <strong>indefinite integral<\/strong> of a function <em>f<\/em> is, by definition, the most general antiderivative of <em>f<\/em>.  Notation for the indefinite integral is shown below.<\/p>\n<p><img decoding=\"async\" class=\"aligncenter size-full wp-image-8691\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Indefinite_integral.gif\" alt=\"Indefinite integral Antidifferentiation\" width=\"178\" height=\"41\" \/><\/p>\n<p>Whenever we work out an indefinite integral, we are doing antidifferentiation.<\/p>\n<h2>Antidifferentiation Formulas<\/h2>\n<p>There are many more formulas and techniques for antidifferentiation.  Fortunately you only need to be aware of the basics for both the AB and BC exams.<\/p>\n<p>The AP Calculus AB exam covers basic antidifferentiation formulas and substitution of variables.<\/p>\n<p>The AP Calculus BC exam includes not only the basic formulas and substitution but also integration by parts (IBP), and simple partial fractions (PF).  This test also has more challenging problems overall.<\/p>\n<p>Note, these rules are all written in terms of indefinite integrals.<\/p>\n<h3>The Basic Rules<\/h2>\n<p>The &#8220;basic&#8221; rules refer to those rules that follow directly from differentiation rules.  Some of the more common rules include the Power Rule, Sum\/Difference Rule, and Constant Multiple Rule.  There are also rules for certain trigonometric, exponential, and other elementary functions.<\/p>\n<p><img decoding=\"async\" class=\"aligncenter size-full wp-image-8694\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Power_rule_integral.gif\" alt=\"Power rule for integrals\" width=\"388\" height=\"44\" \/><\/p>\n<p><img decoding=\"async\" class=\"aligncenter size-full wp-image-8695\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Sum_Diff_Rule_integral.gif\" alt=\"Sum and difference rule for integrals\" width=\"542\" height=\"41\" \/><\/p>\n<p><img decoding=\"async\" class=\"aligncenter size-full wp-image-8693\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Constant_mult_integral.gif\" alt=\"Constant multiple rule for integrals\" width=\"419\" height=\"41\" \/><\/p>\n<p><img decoding=\"async\" class=\"aligncenter size-full wp-image-8739\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Constant_Function_Rule.gif\" alt=\"Constant Function Rule\" width=\"350\" height=\"41\" \/><\/p>\n<p><img decoding=\"async\" class=\"aligncenter size-full wp-image-8741\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Rule_for_1_over_x.gif\" alt=\"Rule for 1\/x\" width=\"273\" height=\"41\" \/><\/p>\n<p><img decoding=\"async\" class=\"aligncenter size-full wp-image-8740\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Exponential_Antiderivatives.gif\" alt=\"Exponential Antiderivatives\" width=\"397\" height=\"88\" \/><\/p>\n<p><img decoding=\"async\" class=\"aligncenter size-full wp-image-8742\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Trig_Antiderivatives.gif\" alt=\"Trigonometric Antiderivatives\" width=\"455\" height=\"274\" \/><\/p>\n<h3>Substitution Rule<\/h3>\n<p>The <strong>Substitution Rule<\/strong>, or <em>u<\/em>-substitution, is a rule that &#8220;reverses&#8221; the Chain Rule.<\/p>\n<p><img decoding=\"async\" class=\"aligncenter size-full wp-image-8746\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Substitution_rule.gif\" alt=\"Substitution Rule\" width=\"547\" height=\"41\" \/><\/p>\n<h3>Integration by Parts<\/h3>\n<p><strong>Integration by Parts<\/strong> (IBP) is a powerful method that may be used when there are certain kinds of products in the integrand. In fact, you can think of IBP as a way to &#8220;reverse&#8221; the Product Rule.<\/p>\n<p>Suppose <em>u<\/em> and <em>v<\/em> are differentiable functions of <em>x<\/em>. Then the IBP formula states that:<\/p>\n<p><img decoding=\"async\" class=\"aligncenter size-full wp-image-8747\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Integration_by_parts.gif\" alt=\"Integration by parts formula\" width=\"179\" height=\"41\" \/><\/p>\n<h3>Partial Fractions<\/h3>\n<p>The method of <strong>Partial Fractions<\/strong> (PF) is an specialized technique for <em>rational functions<\/em>.  The main idea is to break apart the fraction into a sum of\u00a0simpler fractions. <\/p>\n<p>Fortunately, even on the BC exam, you only need to know the easiest cases of PF.  In the simplest cases, the denominator factors into unique <em>linear<\/em> factors.  <\/p>\n<ul>\n<li><strong>Step 1.<\/strong> Factor the denominator.  Each of those factors will become the denominator of its own fraction.\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Partial_fractions.gif\" alt=\"Partial fractions\" width=\"485\" height=\"43\" class=\"aligncenter size-full wp-image-8799\" \/><\/p>\n<\/li>\n<li><strong>Step 2.<\/strong> Then you will have to determine the constant numerators.  There are various algebraic ways to do this.  Perhaps the quickest and easiest way is the <strong>Heaviside cover-up method<\/strong>.\n<p>When there are only linear factors, the Heaviside cover-up method works as follows:<\/p>\n<p>For each factor (<em>x<\/em> &#8211; <em>c<\/em>) cover that factor in the expression.  Then plug the root of that factor (that is, <em>x<\/em> = <em>c<\/em>) into the remaining expression. The result is the correct value of the constant <em>A<\/em> corresponding to that factor.<\/p>\n<\/li>\n<li><strong>Step 3.<\/strong> Finally, integrate each simpler fraction.  In the easiest cases, this involves a simple substitution and the rule for 1\/<em>x<\/em>.  Each fractional term follows the same basic rule:\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Integral_of_simple_fraction.gif\" alt=\"Integral of a simple fractional expression\" width=\"258\" height=\"41\" class=\"aligncenter size-full wp-image-8800\" \/><\/p>\n<\/li>\n<\/ul>\n<h2>Practice Problems<\/h2>\n<p>Let&#8217;s do some antidifferentiation!<\/p>\n<h3>Example 1<\/h3>\n<p>Find the antiderivative of 4<em>x<\/em><sup>3<\/sup> &#8211; 8<em>x<\/em> + 7.<\/p>\n<p>This is a job for the basic rules, including power rule.<\/p>\n<p><img decoding=\"async\" class=\"aligncenter size-full wp-image-8697\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Indefinite_integral_example1.gif\" alt=\"Indefinite integral example\" width=\"421\" height=\"155\" \/><\/p>\n<p>Now let&#8217;s check our work.  Remember, antidifferentiation is the reverse of differentiation.  So all you have to do is find the derivative of your answer and verify that it is the same as the original integrand.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Derivative_of_polynomial.gif\" alt=\"derivative of polynomial\" width=\"283\" height=\"21\" class=\"aligncenter size-full wp-image-8798\" \/><\/p>\n<h3>Example 2<\/h3>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Partial_fractions_example.gif\" alt=\"Partial fractions example\" width=\"209\" height=\"41\" class=\"aligncenter size-full wp-image-8801\" \/><\/p>\n<p>This is a job for partial fractions.  First, verify the numerator has smaller degree than the denominator.  (If it had the same or larger degree, then you would first have to rewrite the integral using <em>polynomial division<\/em>.  Check out <a href=\"https:\/\/www.khanacademy.org\/math\/algebra2\/arithmetic-with-polynomials\/long-division-of-polynomials\/v\/polynomial-division\" target=\"_blank\" rel=\"noopener noreferrer\">this video<\/a> to learn more about long division of polynomials.)<\/p>\n<p>First factor the denominator. <em>x<\/em><sup>2<\/sup> \u2013 7<em>x<\/em> + 12 = (<em>x<\/em> \u2013 3)(<em>x<\/em> \u2013 4).<\/p>\n<p>Next, rewrite the integrand as a sum of fractions with each factor as denominator and unknown constant as numerator.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Partial_fractions_rewrite1.gif\" alt=\"Partial fractions - Rewriting as a sum of fractions\" width=\"374\" height=\"41\" class=\"aligncenter size-full wp-image-8803\" \/><\/p>\n<p>Now use the Heaviside cover-up method for each factor.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Heaviside_method_1.gif\" alt=\"Using Heaviside method 1\" width=\"348\" height=\"43\" class=\"aligncenter size-full wp-image-8804\" \/><\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Heaviside_method_2.gif\" alt=\"Using Heaviside method 2\" width=\"363\" height=\"43\" class=\"aligncenter size-full wp-image-8805\" \/><\/p>\n<p>Finally, plug your constants in and integrate.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/01\/Partial_fractions_example_solution.gif\" alt=\"Partial fractions example worked out solution\" width=\"396\" height=\"70\" class=\"aligncenter size-full wp-image-8806\" \/><\/p>\n<h2>Summary<\/h2>\n<p>Antidifferentiation is the reverse of differentiation.  It is the same as finding an antiderivative for a function.  The indefinite integral is the most general antiderivative.  The antidifferentiation techniques required on the exams include: <\/p>\n<ul>\n<li>Basic formulas<\/li>\n<li>Substitution<\/li>\n<li>Integration by Parts (BC only)<\/li>\n<li>Partial Fractions (BC only)<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Antidifferentiation is an essential tool for evaluating integrals. In fact, you might say that antidifferentiation is pretty much the same thing as finding an indefinite integral. When we antidifferentiate a function, we are simply finding another function whose derivative is equal to the one we started with. What is Antidifferentiation? Antidifferentiation is the reverse of [&hellip;]<\/p>\n","protected":false},"author":223,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[240],"tags":[241],"ppma_author":[24932],"class_list":["post-8788","post","type-post","status-publish","format-standard","hentry","category-ap","tag-ap-calculus"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v21.7 (Yoast SEO v21.7) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>AP Calculus Exam Review: Antidifferentiation - Magoosh Blog | High School<\/title>\n<meta name=\"description\" content=\"Antidifferentiation is pretty much the same thing as finding an indefinite integral. 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D. in mathematics from The Ohio State University in 2008 (Go Bucks!!). He received his BA in Mathematics with a minor in computer science from Oberlin College in 2002. In addition, Shaun earned a B. Mus. from the Oberlin Conservatory in the same year, with a major in music composition. Shaun still loves music -- almost as much as math! -- and he (thinks he) can play piano, guitar, and bass. 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