{"id":10711,"date":"2017-10-24T21:18:15","date_gmt":"2017-10-25T04:18:15","guid":{"rendered":"https:\/\/magoosh.com\/hs\/?p=10711"},"modified":"2018-10-24T03:57:12","modified_gmt":"2018-10-24T10:57:12","slug":"ap-calculus-bc-review-geometric-series","status":"publish","type":"post","link":"https:\/\/magoosh.com\/hs\/ap\/ap-calculus-bc-review-geometric-series\/","title":{"rendered":"AP Calculus BC Review: Geometric Series"},"content":{"rendered":"<p>What is a geometric series?  A series is the sum of the terms of a sequence.  What makes the series <em>geometric<\/em> is that each term is a power of a constant base.  For example,<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/sum_reciprocals_powers_of_two.gif\" alt=\"\" width=\"244\" height=\"38\" class=\"aligncenter size-full wp-image-10859\" \/><\/p>\n<p>Each term in this series is a power of 1\/2.  Equivalently, each term is half of its predecessor.  Whenever there is a <em>constant ratio<\/em> from one term to the next, the series is called <em>geometric<\/em>.<\/p>\n<p>Read on to find out more!<\/p>\n<figure id=\"attachment_10857\" aria-describedby=\"caption-attachment-10857\" style=\"width: 500px\" class=\"wp-caption aligncenter\"><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/500px-Geometric_progression_convergence_diagram.svg_.png\" alt=\"Geometric illustration of the convergence of a series\" width=\"500\" height=\"250\" class=\"size-full wp-image-10857\" srcset=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/500px-Geometric_progression_convergence_diagram.svg_.png 500w, https:\/\/magoosh.com\/hs\/files\/2017\/07\/500px-Geometric_progression_convergence_diagram.svg_-300x150.png 300w\" sizes=\"(max-width: 500px) 100vw, 500px\" \/><figcaption id=\"caption-attachment-10857\" class=\"wp-caption-text\">The series 1 + 1\/2 + 1\/4 + 1\/8 + 1\/16 + &#8230;. has a finite sum.  The area of the large rectangle is equal to 2, and each smaller square or rectangle fits snugly into it.<\/figcaption><\/figure>\n<h2>Infinity and Zeno&#8217;s Paradox<\/h2>\n<p>Typically there are infinitely many terms to add up in a series.  So it&#8217;s usually very difficult to determine whether the answer is finite, let alone what the value of the sum could be.  <\/p>\n<p><em>But how can you add up infinitely many terms in the first place???<\/em><\/p>\n<p>This question puzzled the ancient Greek philosophers and mathematicians.  In fact, the idea of infinity perplexed Zeno of Elea (c. 490 &#8211; c. 430 BC) so much that he concluded that motion must be impossible.<\/p>\n<p><iframe title=\"Achilles and the Tortoise - 60-Second Adventures in Thought (1\/6)\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/skM37PcZmWE?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe><\/p>\n<p>Of course we all experience motion every day.  In a real life race between Achilles and the Tortoise, we all know that Achilles would eventually overtake the slowpoke Tortoise.<\/p>\n<p>The key is a geometric series. Even though there may be an infinite number of lengths that Achilles must get through to catch the Tortoise, each length itself is smaller by a <em>constant ratio<\/em> compared to the last.  When you add up the terms &#8212; even an infinite number of them &#8212; you&#8217;ll end up with a finite answer!<\/p>\n<h2>Geometric Series<\/h2>\n<p>A geometric series is the sum of the powers of a constant base <em>r<\/em>, often including a constant coefficient <em>a<\/em> in front of each term.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/geometric_series.gif\" alt=\"Geometric series\" width=\"213\" height=\"50\" class=\"aligncenter size-full wp-image-10899\" \/><\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_2.gif\" alt=\"Geometric series written out\" width=\"252\" height=\"18\" class=\"aligncenter size-full wp-image-10909\" \/><\/p>\n<p>So, each of the following is geometric.<\/p>\n<ul>\n<li>1 + 3 + 9 + 27 + 81 + &#8230; (<em>r<\/em> = 3, <em>a<\/em> = 1).<\/li>\n<li>2\/3 &#8211; 2\/9 + 2\/27 &#8211; 2\/81 + &#8230; (<em>r<\/em> = -1\/3, <em>a<\/em> = 2\/3).<\/li>\n<li>1 &#8211; 1 + 1 &#8211; 1 + 1 &#8211; 1 + &#8230; (<em>r<\/em> = -1, <em>a<\/em> = 1).<\/li>\n<\/ul>\n<p>On the other hand, the following series are <em>not<\/em> geometric.<\/p>\n<ul>\n<li>2 + 4 + 6 + 8 + 10 + &#8230; (arithmetic sequence with common difference <em>d<\/em> = 2)<\/li>\n<li>1 + 4 + 9 + 16 + 25 + 36 + &#8230; (sum of squares)<\/li>\n<li>1 + 1\/2 + 1\/3 + 1\/4 + 1\/5 + 1\/6 + &#8230; (Harmonic Series)<\/li>\n<\/ul>\n<h3>Convergence and Divergence<\/h3>\n<p>There is a straightforward test to decide whether any geometric series converges or diverges.<\/p>\n<ul>\n<li>If |<em>r<\/em>| &lt; 1, then the series converges.<\/li>\n<li>If |<em>r<\/em>| &ge; 1, then the series diverges.<\/li>\n<\/ul>\n<p>Furthermore, whenever the series does converge, there is a simple formula to find its sum:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/04\/geometric_series.gif\" alt=\"Formula for the sum of a geometric series\" width=\"220\" height=\"50\" class=\"aligncenter size-full wp-image-9745\" \/><\/p>\n<h3>Proof of the Sum Formula<\/h3>\n<p>In order to really understand why the formula works the way it does, let&#8217;s dig into a proof of the result.<\/p>\n<p>First of all, let&#8217;s see what the <em>k<\/em>th partial sum of the series &Sigma; <em>ar<sup>n<\/sup><\/em> looks like.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_partial_sum.gif\" alt=\"geometric series partial sum\" width=\"355\" height=\"53\" class=\"aligncenter size-full wp-image-10910\" \/><\/p>\n<p>Notice that if you multiplied <em>s<sub>k<\/sub><\/em> by another factor of the base <em>r<\/em>, then you would get:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_partial_sum2.gif\" alt=\"Multiplying each term of the partial sum for the geometric series by r.\" width=\"335\" height=\"48\" class=\"aligncenter size-full wp-image-10911\" \/><\/p>\n<p>The majority of the terms match with those of the original <em>s<sub>k<\/sub><\/em>.  So, if we subtracted the two expressions, most of the terms would cancel.  After a bit of factoring and solving for the unknown sum, we can derive a useful formula.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/deriving_geom_sum_formula.gif\" alt=\"Deriving the geometric sum formula\" width=\"397\" height=\"151\" class=\"aligncenter size-full wp-image-10912\" \/><\/p>\n<p>Next, we apply the limit to determine what happens in the infinite series.  The key is that <em>r<sup>x<\/sup><\/em> &rarr; 0 as <em>x<\/em> &rarr; &infin; so long as |<em>r<\/em>| &lt; 1. On the other hand, if |<em>r<\/em>| &ge; 1, or <em>r<\/em> = &plusmn; 1, then <em>r<sup>x<\/sup><\/em> diverges or there would be a nasty division by zero.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/deriving_geom_sum_formula_final.gif\" alt=\"Deriving geometric sum formula, final steps\" width=\"321\" height=\"138\" class=\"aligncenter size-full wp-image-10913\" \/><\/p>\n<h2>Examples from the AP Calculus BC Exam<\/h2>\n<h3>A Simple Series<\/h3>\n<p>Find the sum of 2\/3 &#8211; 2\/9 + 2\/27 &#8211; 2\/81 + &#8230; <\/p>\n<h4>Solution<\/h4>\n<p>The common ratio is <em>r<\/em> = -1\/3, and the initial term gives the coefficient: <em>a<\/em> = 2\/3.<\/p>\n<p>Because |<em>r<\/em>| = 1\/3 &lt; 1, the series converges.  All that remains is to plug <em>r<\/em> and <em>a<\/em> into the sum formula.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_example1_answer.gif\" alt=\"The sum of this series is 1\/2\" width=\"141\" height=\"148\" class=\"aligncenter size-full wp-image-10921\" srcset=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_example1_answer.gif 141w, https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_example1_answer-30x30.gif 30w\" sizes=\"(max-width: 141px) 100vw, 141px\" \/><\/p>\n<p>Therefore, the sum is exactly 1\/2.  <\/p>\n<p>By the way, it&#8217;s always a good idea to check your work.  If you add up just the first four terms, you get 2\/3 &#8211; 2\/9 + 2\/27 &#8211; 2\/81  = 0.4938, which is already pretty close to 0.5.<\/p>\n<h3>Rewriting the Terms<\/h3>\n<p>What is the value of &nbsp;<img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_example2.gif\" alt=\"sum of 8^n\/3^(n+2)\" width=\"65\" height=\"51\" class=\"alignnone size-full wp-image-10922\" srcset=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_example2.gif 65w, https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_example2-30x24.gif 30w\" sizes=\"(max-width: 65px) 100vw, 65px\" \/>&nbsp;?<\/p>\n<h4>Solution<\/h4>\n<p>This series is definitely geometric.  However, in its current form it might be hard to see what is <em>r<\/em> and what is <em>a<\/em>.  Let&#8217;s write out the first few terms of the series explicitly.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_example2_terms.gif\" alt=\"8\/27 + 64\/81 + 512\/243 + ....\" width=\"286\" height=\"95\" class=\"aligncenter size-full wp-image-10923\" \/><\/p>\n<p>Now we can see that <em>a<\/em> = 8\/27.<\/p>\n<p>The common ratio is: (64\/81) \/ (8\/27) = 8\/3 = <em>r<\/em>. <\/p>\n<p>It&#8217;s tempting to jump straight to the sum formula, but if you did so, then you would get this one wrong.  The trouble is that |<em>r<\/em>| &ge; 1, which implies that this series <strong>diverges<\/strong>. (There is no finite sum.)<\/p>\n<h3>Series of Functions<\/h3>\n<p>If <img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_function.gif\" alt=\"Geometric series of functions\" width=\"156\" height=\"50\" class=\"alignnone size-full wp-image-10919\" \/>, then what is the value of <em>f<\/em>(&pi;\/3)?<\/p>\n<h4>Solution<\/h4>\n<p>The geometric series formula works just the same when there are variables like <em>x<\/em> involved as well.  Here, the common ratio (base) is <em>r<\/em> = sin<sup>2<\/sup> <em>x<\/em>, which is always bounded by 1.<\/p>\n<p>Then, once you get an explicit formula for <em>f<\/em>(<em>x<\/em>), you can plug in <em>x<\/em> = &pi;\/3.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/geom_series_function_worked_out.gif\" alt=\"final answer for the example\" width=\"268\" height=\"187\" class=\"aligncenter size-full wp-image-10920\" \/><\/p>\n<h2>0.999999&#8230; = 1???<\/h2>\n<p>One of my favorite demonstrations of the geometric series formula is in proving the paradoxical fact <img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/nine_repeating.gif\" alt=\".99999.... = 1\" width=\"55\" height=\"16\" class=\"alignnone size-full wp-image-10908\" srcset=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/nine_repeating.gif 55w, https:\/\/magoosh.com\/hs\/files\/2017\/07\/nine_repeating-30x9.gif 30w\" sizes=\"(max-width: 55px) 100vw, 55px\" \/>.<\/p>\n<p>First of all, we have to write the decimal as a sum.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/sum0.9999.gif\" alt=\"writing 0.99999,,, as a sum\" width=\"301\" height=\"92\" class=\"aligncenter size-full wp-image-10916\" \/><\/p>\n<p>The last line shows that this sum is geometric, with <em>a<\/em> = 9\/10 and common ratio <em>r<\/em> = 1\/10.  Because |<em>r<\/em>| = 1\/10 &lt; 1, we know that the sum must converge.  Now use the formula to find the sum.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/sum0.9999_answer.gif\" alt=\"Summing the series to find 0.99999.....\" width=\"295\" height=\"168\" class=\"aligncenter size-full wp-image-10917\" \/><\/p>\n<p>While this result may be very surprising at first, it&#8217;s definitely true.  Indeed, it&#8217;s just as true as the fact that Achilles must eventually catch up to the Tortoise!<\/p>\n<figure id=\"attachment_10918\" aria-describedby=\"caption-attachment-10918\" style=\"width: 640px\" class=\"wp-caption aligncenter\"><img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/1464834963_6f1ba27810_z.jpg\" alt=\"grumpy tortoise\" width=\"640\" height=\"428\" class=\"size-full wp-image-10918\" srcset=\"https:\/\/magoosh.com\/hs\/files\/2017\/07\/1464834963_6f1ba27810_z.jpg 640w, https:\/\/magoosh.com\/hs\/files\/2017\/07\/1464834963_6f1ba27810_z-300x201.jpg 300w, https:\/\/magoosh.com\/hs\/files\/2017\/07\/1464834963_6f1ba27810_z-600x401.jpg 600w\" sizes=\"(max-width: 640px) 100vw, 640px\" \/><figcaption id=\"caption-attachment-10918\" class=\"wp-caption-text\">Grumpy Tortoise is grumpy.  Photo by <a href=\"https:\/\/www.flickr.com\/photos\/ekilby\/\" target=\"_blank\" rel=\"noopener noreferrer\">Erik Kilby<\/a>.<\/figcaption><\/figure>\n<h2>Summary<\/h2>\n<p>Let&#8217;s recap.<\/p>\n<ol>\n<li>A geometric series is the sum of powers of a constant base.<\/li>\n<li>Adjacent terms always have a constant ratio <em>r<\/em>.<\/li>\n<li>If |<em>r<\/em>| &lt; 1, then the series converges to:<br \/>\n<img decoding=\"async\" src=\"https:\/\/magoosh.com\/hs\/files\/2017\/04\/geometric_series.gif\" alt=\"Formula for the sum of a geometric series\" width=\"220\" height=\"50\" class=\"aligncenter size-full wp-image-9745\" \/><\/li>\n<li>If |<em>r<\/em>| &ge; 1, then the series diverges.  <\/li>\n<\/ol>\n<p>For more about series, you can check out the following review articles.<\/p>\n<ul>\n<li><a href=\"https:\/\/magoosh.com\/hs\/ap\/ap-calculus-bc-review-series-fundamentals\/\">AP Calculus BC Review: Series Fundamentals<\/a><\/li>\n<li><a href=\"https:\/\/magoosh.com\/hs\/ap\/ap-calculus-bc-review-series-convergence\/\">AP Calculus BC Review: Series Convergence<\/a><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>What is a geometric series? A series is the sum of the terms of a sequence. What makes the series geometric is that each term is a power of a constant base. For example, Each term in this series is a power of 1\/2. Equivalently, each term is half of its predecessor. Whenever there is [&hellip;]<\/p>\n","protected":false},"author":223,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[240],"tags":[241],"ppma_author":[24932],"class_list":["post-10711","post","type-post","status-publish","format-standard","hentry","category-ap","tag-ap-calculus"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v21.7 (Yoast SEO v21.7) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>AP Calculus BC Review: Geometric Series - Magoosh Blog | High School<\/title>\n<meta name=\"description\" content=\"A geometric series is a sum in which each term is a power of a constant base. 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