Here’s this week’s question– we’ll be posting up the answer tomorrow, good luck!

In how many different ways can 3 identical green shirts and 3 identical red shirts be distributed among 6 children such that each child receives a shirt?

In the given example , there are two set of shirts (green and red) , each set consisting of the 3 identical shirt .
Hence , the total no of ways in which shirts will be distributed amongst 6 children will be [ 6! / (3! * 3!) ] = 20

Magoosh blog comment policy: To create the best experience for our readers, we will only approve comments that are relevant to the article, general enough to be helpful to other students, concise, and well-written! 😄 Due to the high volume of comments across all of our blogs, we cannot promise that all comments will receive responses from our instructors.

We highly encourage students to help each other out and respond to other students' comments if you can!

If you are a Premium Magoosh student and would like more personalized service from our instructors, you can use the Help tab on the Magoosh dashboard. Thanks!

correct answer is A,20

yep… answer is 20, however this is a problem from Permutations and Combinations.

Hi, Siva

You’re right– about both the answer and the mistake. Thanks for the heads up!

the ans is 720… the first child can receive the shirt in 6 ways the 2nd boy in 5 ways and so on…. 6*5*4*3*2*1=720 ways

This one’s an easy one. (Rather a very basic question)

Correct Answer: A) 20

6! / (3!x3!) = 20

The correct answer is A. 20

In the given example , there are two set of shirts (green and red) , each set consisting of the 3 identical shirt .

Hence , the total no of ways in which shirts will be distributed amongst 6 children will be [ 6! / (3! * 3!) ] = 20