Here’s this week’s question– we’ll be posting up the answer tomorrow, good luck!

In how many different ways can 3 identical green shirts and 3 identical red shirts be distributed among 6 children such that each child receives a shirt?

In the given example , there are two set of shirts (green and red) , each set consisting of the 3 identical shirt . Hence , the total no of ways in which shirts will be distributed amongst 6 children will be [ 6! / (3! * 3!) ] = 20

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correct answer is A,20

yep… answer is 20, however this is a problem from Permutations and Combinations.

Hi, Siva

You’re right– about both the answer and the mistake. Thanks for the heads up!

the ans is 720… the first child can receive the shirt in 6 ways the 2nd boy in 5 ways and so on…. 6*5*4*3*2*1=720 ways

This one’s an easy one. (Rather a very basic question)

Correct Answer: A) 20

6! / (3!x3!) = 20

The correct answer is A. 20

In the given example , there are two set of shirts (green and red) , each set consisting of the 3 identical shirt .

Hence , the total no of ways in which shirts will be distributed amongst 6 children will be [ 6! / (3! * 3!) ] = 20