This week’s practice question is Numeric Entry, so no answer choices are given! You’ll have to type the number in to submit your answer. Good luck, we’ll be posting the answer and explanation tomorrow!

Answer is 1.
.
Concepts: x ^ -1 = 1/x [or, x^-n = 1/(x^n)]
& 1/ (x * y) = 1/x * 1/y [rudimentary, both of these]
.
Given expression,
.
(2^-n /3) * (3^-n /2) = 1/36
using the 2 concepts this becomes,
1/3 * 1/2 * 1/(2^n) * 1/(3^n) = 1/36
Multiplying both sides by 6,
1/(2^n * 3^n) = 1/6
.
This simplifies to 2^n * 3^n = 6.
.
We can substitute 1 as the value of n in the equation to verify.
.
MN

Magoosh blog comment policy: To create the best experience for our readers, we will only approve comments that are relevant to the article, general enough to be helpful to other students, concise, and well-written! 😄 Due to the high volume of comments across all of our blogs, we cannot promise that all comments will receive responses from our instructors.

We highly encourage students to help each other out and respond to other students' comments if you can!

If you are a Premium Magoosh student and would like more personalized service from our instructors, you can use the Help tab on the Magoosh dashboard. Thanks!

Difficulty level of question?

the Ans—->=1/(3*2^n)*(1/(2*3*n)=1/36—->=(2*3*(2^n*3^n)=36——>

(6*2^n*3^n)=36

=(2*3)^n=6—->n=1

Ans: n = 1

n=1

1/3 * 1/2 * 1/(2^n) * 1/(3^n)=1/(2^2 * 3^2) 1/(2*3)^n = 1/(2*3) is equivalent to 1/a^x = 1/a OR a^-x = a^-1, where a=2*3

-x=-1 and x=1

enter 1 as answer for this question 🙂

Ans is 1….

Answer is 1.

.

Concepts: x ^ -1 = 1/x [or, x^-n = 1/(x^n)]

& 1/ (x * y) = 1/x * 1/y [rudimentary, both of these]

.

Given expression,

.

(2^-n /3) * (3^-n /2) = 1/36

using the 2 concepts this becomes,

1/3 * 1/2 * 1/(2^n) * 1/(3^n) = 1/36

Multiplying both sides by 6,

1/(2^n * 3^n) = 1/6

.

This simplifies to 2^n * 3^n = 6.

.

We can substitute 1 as the value of n in the equation to verify.

.

MN

The value of N is 3.

I hope i’m right… haha