{"id":9203,"date":"2020-01-10T18:56:41","date_gmt":"2020-01-11T02:56:41","guid":{"rendered":"https:\/\/magoosh.com\/gmat\/?p=9203"},"modified":"2021-03-02T10:47:19","modified_gmt":"2021-03-02T18:47:19","slug":"common-gmat-math-mistakes","status":"publish","type":"post","link":"https:\/\/magoosh.com\/gmat\/common-gmat-math-mistakes\/","title":{"rendered":"Common GMAT Math Mistakes"},"content":{"rendered":"<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/image-gmat-header-mathMistake.jpg\" width=\"1200\" height=\"600\" class=\"aligncenter size-full wp-image-8812\" srcset=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/image-gmat-header-mathMistake.jpg 1200w, https:\/\/magoosh.com\/gmat\/files\/2012\/09\/image-gmat-header-mathMistake-300x150.jpg 300w, https:\/\/magoosh.com\/gmat\/files\/2012\/09\/image-gmat-header-mathMistake-768x384.jpg 768w, https:\/\/magoosh.com\/gmat\/files\/2012\/09\/image-gmat-header-mathMistake-600x300.jpg 600w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p>Learn the cluster of the most common <a href=\"https:\/\/magoosh.com\/gmat\/what-kind-of-math-is-on-the-gmat-breakdown-of-quant-concepts-by-frequency\/\">GMAT math<\/a> mistakes, mistakes that the exam regularly exploits so you can avoid these pitfalls.<\/p>\n<p>&nbsp;<\/p>\n<h2>Pattern-Matching,<br \/>\nGood and Bad<\/h2>\n<p>The human brain is, far and away, the best pattern-matching machine we have ever seen.  No computer comes close.  We match patterns for all kinds of things: facial recognition, movies, neighborhood, assessing whether someone is loony, assessing whether someone would make a good friend, etc.  Needless to say, because we do so much pattern-matching, our choices are not spot-on correct 100% of the time.<\/p>\n<p>&nbsp;<\/p>\n<h2>Mathematical Patterns<\/h2>\n<p>What&#8217;s germane to GMAT Math is that we also learn and understand math via patterns.  Like all things in mathematics, what&#8217;s mathematically true is absolutely precise, and even a slight change from that may be completely false.  That simply does in our pattern-matching right-brain, which likes to fudge to fit things.  Hence, there are a some very predictably mathematical patterns that people think are true, or suspect are true, even though they are blatantly false.  And, of course, dozens of GMAT Math questions are designed to probe exactly those areas!<\/p>\n<p>&nbsp;<\/p>\n<h2>Some True Patterns<\/h2>\n<p>First of all, let&#8217;s talk about two true patterns.  True pattern #1 is the <strong>Distributive Law<\/strong>, which says that <em>multiplication distributes over addition &amp; subtraction<\/em>.<\/p>\n<p align=\"center\"><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_990.5_53d39daa4f6ca871917f21aa382afbd5.png\" style=\"vertical-align:-9.5px; display: inline-block ;\" alt=\"a*(b + c) = ab + ac\" title=\"a*(b + c) = ab + ac\"\/><\/p>\n<p>&nbsp;<\/p>\n<p>Incidentally, when you go from left to right, the action is called &#8220;distributing&#8221;, and when you go right to left, the action is called &#8220;factoring out.&#8221;  Those two are a complement pair of actions.  <a title=\"GMAT Math: Factors\" href=\"https:\/\/magoosh.com\/gmat\/gmat-math-factors\/\" target=\"_blank\" rel=\"noopener noreferrer\">Factoring out<\/a> is a move that is often helpful in solving the more algebraic GMAT problems.<\/p>\n<p>The second doesn&#8217;t have a universally recognized name like the first, although it&#8217;s sometimes called the &#8220;Distributive Law for Exponents,&#8221; which says that <em>exponents distribute over multiplication&amp; division<\/em>.<\/p>\n<p align=\"center\"><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_984_f24050a714acdcf868737f527cbd26b9.png\" style=\"vertical-align:-16px; display: inline-block ;\" alt=\"(ab)^n = (a^n)(b^n)\" title=\"(ab)^n = (a^n)(b^n)\"\/><\/p>\n<p align=\"center\"><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_967_dbffdb801cac3da8df1820ab1c70fa3d.png\" style=\"vertical-align:-33px; display: inline-block ;\" alt=\"(a\/b)^n = (a^n)\/(b^n)\" title=\"(a\/b)^n = (a^n)\/(b^n)\"\/><\/p>\n<p>&nbsp;<\/p>\n<p>Two special cases of this are square-roots and reciprocals, which are really specific cases of exponents.  They both distribute over multiplication.<\/p>\n<p>&nbsp;<\/p>\n<p align=\"center\"><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_986_5c6733ff2673ad4a50245447d63dc906.png\" style=\"vertical-align:-14px; display: inline-block ;\" alt=\"sqrt{ab} = (sqrt{a})*(sqrt{b})\" title=\"sqrt{ab} = (sqrt{a})*(sqrt{b})\"\/>                 <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_984_ac1068380b60911a1f9dd4dd9223fe88.png\" style=\"vertical-align:-16px; display: inline-block ;\" alt=\"1\/{ab} = {1\/a}*{1\/b}\" title=\"1\/{ab} = {1\/a}*{1\/b}\"\/><\/p>\n<p>&nbsp;<\/p>\n<p>All of these are 100% percent true.<\/p>\n<p>&nbsp;<\/p>\n<h2>The Not-So-True Patterns<\/h2>\n<p>You can almost see where this is going. It&#8217;s absolutely true that multiplication distributes over addition and subtraction.  It&#8217;s absolutely true that exponents (including square-roots and reciprocals) distribute over multiplication and division.   BUT, it&#8217;s 100% <strong><em><span style=\"text-decoration: underline;\">false<\/span><\/em><\/strong> that exponents, square-roots, or reciprocals distribute over addition and subtraction at any time in any way.  The following red equations are examples of false extensions of the pattern.<\/p>\n<p>&nbsp;<\/p>\n<p align=\"center\"><a href=\"https:\/\/magoosh.com\/gmat\/files\/2012\/01\/false-equations.png\"><img decoding=\"async\" class=\"alignnone size-full wp-image-694\" src=\"https:\/\/magoosh.com\/gmat\/files\/2012\/01\/false-equations.png\" alt=\"\" width=\"543\" height=\"201\" srcset=\"https:\/\/magoosh.com\/gmat\/files\/2012\/01\/false-equations.png 543w, https:\/\/magoosh.com\/gmat\/files\/2012\/01\/false-equations-300x111.png 300w\" sizes=\"(max-width: 543px) 100vw, 543px\" \/><\/a><\/p>\n<p>Take a good look at these.  I encourage you to plug in numbers to verify that each one is false.  They are <em>close<\/em> to the correct laws above, but in characteristic mathematical fashion, &#8220;close&#8221; here means &#8220;dead wrong.&#8221; Questions that encourage you to make one of these mistakes simply litter the GMAT math sections.<\/p>\n<p>&nbsp;<\/p>\n<h2>Robust Errors<\/h2>\n<p>The pattern-matching function of the brain runs deep, as does our trust in it.  Just because you can identify the faulty pattern consciously in a lucid moment doesn&#8217;t mean you won&#8217;t fall into the same mistake again.<\/p>\n<p>In math pedagogy, these are called &#8220;robust errors&#8221;: even when you understand clearly why these are false, it&#8217;s as if the pattern-matching machinery of the mind draws you back to making the same mistake.  If you less than 100% crystal clear about these mistakes, you will make them when you are tired, when you are less focused, and when you are stressed \u2013 for example, during the GMAT.  I highly recommend that you bookmark this page and reread this article, each time reacquainting yourself with why each mistake is mathematically unsound.  I highly recommend you start making a log of the GMAT practice questions that, in some way, solicited one of these mistakes \u2013 and whether you fell for it or not.<\/p>\n<p>Taken as a group, these must be the single greatest source of algebra errors on the GMAT.  If, through practice, you can learn to catch yourself and prevent yourself from making one of these mistakes every time, this will phenomenally improve your GMAT Quantitative Score.<\/p>\n<h2>Dropping the negative sign<\/h2>\n<p>Suppose you are solving the equation<\/p>\n<p>5 \u2013 2x = 13<\/p>\n<p>We want to isolate x.  One tactic would be to begin by subtracting 5 from both sides.  On the right, 13 \u2013 5 = 8.  On the left, the 5&#8217;s cancel, but with what are we left?  It would be a mistake to subtract 5 and wind up with:<\/p>\n<p><a href=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img1.png\"><img decoding=\"async\" class=\"alignnone size-full wp-image-2746\" title=\"cgmm_img1\" src=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img1.png\" alt=\"\" width=\"67\" height=\"34\" \/><\/a><\/p>\n<p>I have that in red, with an unequal sign, to emphasize that it is wrong.  Of course, the mistake is: when we subtract the 5 and get rid of it, the 2x term does not magically change from negative to positive.  It still has a negative sign in front of it.  Therefore, the next steps are:<\/p>\n<p>-2x = 8<\/p>\n<p>x = -4<\/p>\n<p>Actually, if you notice any tendency toward making this mistake, I highly recommend: make your first step to <strong><em>add any subtracted variable to other side<\/em><\/strong>, to make it positive.  If your first step, automatically, is to make the variable positive, then  you will be considerably less likely to make this mistake.<\/p>\n<p>&nbsp;<\/p>\n<h2>Dividing by the numerator<\/h2>\n<p>Suppose you have this equation to solve:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_984_67bd44dde77f93ecea628e2b003940ea.png\" style=\"vertical-align:-16px; display: inline-block ;\" alt=\"5\/x = 20\" title=\"5\/x = 20\"\/><\/p>\n<p>Both sides are clearly divisible by 5, so one possible first step would be to divide by sides by 5.  On the right, <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_984_8ab5eb03a4fa8ffb45d83742ced10943.png\" style=\"vertical-align:-16px; display: inline-block ;\" alt=\"20\/5 = 4\" title=\"20\/5 = 4\"\/>.  On the left, the 5&#8217;s cancel, but the question is: what is on the left side after dividing by 5?  Just x?  No!  That&#8217;s a very tempting mistake to make!  In the equation above, x is in the denominator, and &#8220;being in the denominator&#8221; is not a condition that goes away just because a number in the numerator is cancelled.  If we divide by sides by 5, the proper result is<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_984_0acbea55c3a906799429f7e4c3ae68e4.png\" style=\"vertical-align:-16px; display: inline-block ;\" alt=\"1\/x = 4\" title=\"1\/x = 4\"\/><\/p>\n<p>You can multiply by x, and divide by 4 to solve &#8212;- or, you simply could take the reciprocal of both sides (always a completely legitimate move when you have fraction = number or fraction = fraction).  Either way, the answer is <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_984_c57ea4cbbc05574dc8ffdd2899bd9abf.png\" style=\"vertical-align:-16px; display: inline-block ;\" alt=\"x = 1\/4\" title=\"x = 1\/4\"\/>.<\/p>\n<p>&nbsp;<\/p>\n<h2>Distributing a square<\/h2>\n<p>These next three mistakes are part of a broad category.  First of all, one of most fundamental laws underlying all arithmetic and algebra is a law called the Distributive Law.  Symbolically, it states<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_990.5_b4d5567e9fa4bd17c0f8729e3cc03b7a.png\" style=\"vertical-align:-9.5px; display: inline-block ;\" alt=\"A*(B + C) = A*B + A*C\" title=\"A*(B + C) = A*B + A*C\"\/><\/p>\n<p>When read left-to-right, it is called distributing: we distribute A over (B + C).   When this same equation is read right-to-left, it is called &#8220;factoring out.&#8221;  See <a href=\"https:\/\/magoosh.com\/gmat\/adding-and-subtracting-powers-on-the-gmat\/\">this post<\/a> for a more extended panegyric to the Distributive Law, in a more advanced context.  That equation is 100% true, 100% of the time.  In words, we can say: multiplication distributes over addition and subtraction.  It&#8217;s one of the most fundamental laws in all of mathematics.<\/p>\n<p>That pattern is very important, and has a wide variety of applications in elementary and advanced mathematics.  For some reason, though, this pregnant pattern is ripe for vast over-generalization.  The mind seems almost magnetically drawn to distributing all kind of things other than multiplication over addition and subtraction.<\/p>\n<p>One example is: an exponent.  Suppose we are asked to expand algebraically the expression:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_990.5_affaadae36a423a5f313441e60700947.png\" style=\"vertical-align:-9.5px; display: inline-block ;\" alt=\"(x + 5)^2\" title=\"(x + 5)^2\"\/><\/p>\n<p>Be careful here, because unless you are a pro at math, your mind is going to be magnetically attracted to the wrong thing to do.  Here&#8217;s the wrong thing to do:<\/p>\n<p><a href=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img2.png\"><img decoding=\"async\" class=\"alignnone size-full wp-image-2747\" title=\"cgmm_img2\" src=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img2.png\" alt=\"\" width=\"160\" height=\"34\" \/><\/a><\/p>\n<p>If you notice, this mistake involves following the Distributive Law pattern, but with an exponent rather than with multiplication.  That&#8217;s illegal.  What&#8217;s the correct procedure?  Well, squaring anything means <strong><span style=\"text-decoration: underline\">multiplying it by itself<\/span><\/strong>, so the first step would be:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_990.5_5c736b0ad881d7adc03a24b9b486b391.png\" style=\"vertical-align:-9.5px; display: inline-block ;\" alt=\"(x + 5)^2 = (x + 5)*(x + 5)\" title=\"(x + 5)^2 = (x + 5)*(x + 5)\"\/><\/p>\n<p>From there, you would FOIL out the expression.  That&#8217;s the step-by-step way to get to the answer.  It can be a very handy shortcut to have the following two patterns memorized.<\/p>\n<p><strong>The Square of a Sum<\/strong>: <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_990.5_9ffd306bb494aacaca4c427f775fdfc9.png\" style=\"vertical-align:-9.5px; display: inline-block ;\" alt=\"(a + b)^2 = a^2 + 2ab + b^2\" title=\"(a + b)^2 = a^2 + 2ab + b^2\"\/><\/p>\n<p><strong>The Square of a Difference<\/strong>: <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_990.5_1b3e6a4e5fc9d3d8ec84024eb29381b6.png\" style=\"vertical-align:-9.5px; display: inline-block ;\" alt=\"(a - b)^2 = a^2 - 2ab + b^2\" title=\"(a - b)^2 = a^2 - 2ab + b^2\"\/><\/p>\n<p>Those formulas take into account the proper FOILing.  Memorizing these can be a time-saving shortcut and also might help you to remember to avoid Mistake #3 here.<\/p>\n<p>&nbsp;<\/p>\n<h2>Distributing a fraction<\/h2>\n<p>This is another mistake of the &#8220;over-extend the Distributive Law to regions that are not valid&#8221; variety.  Here is the succinct way to express this mistake.<\/p>\n<p><a href=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img3.png\"><img decoding=\"async\" class=\"alignnone size-full wp-image-2748\" title=\"cgmm_img3\" src=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img3.png\" alt=\"\" width=\"131\" height=\"56\" \/><\/a><\/p>\n<p>In other words, you can neither combine nor separate fractions by additions in the denominator.  This one has far-reaching ramifications.  For example, in the following fraction \u2026<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_984_20f52dd04b2c20dd944c302f23846e18.png\" style=\"vertical-align:-16px; display: inline-block ;\" alt=\"12\/{3x + 8}\" title=\"12\/{3x + 8}\"\/><\/p>\n<p>\u2026 what can you cancel?  NOTHING!  If the 12 were over <span style=\"text-decoration: underline\">just<\/span> the 3x, or if the 12 were <span style=\"text-decoration: underline\">just<\/span> over the 8, then you would be able to cancel, but because you can&#8217;t separate the fraction, you can do absolutely no canceling.  BTW, in the fraction \u2026.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_984_fd23a7ad33cb922bbec8de34b7519e48.png\" style=\"vertical-align:-16px; display: inline-block ;\" alt=\"{5x + 9}\/15\" title=\"{5x + 9}\/15\"\/><\/p>\n<p>\u2026 even though some cancellation is possible, you can&#8217;t do any while the fraction is still like this.  You have to separate it, by the addition in the numerator (a 100% legitimate move) and then you can cancel:<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_984_fb402e48aec4cbf8d1d975ed6544ecef.png\" style=\"vertical-align:-16px; display: inline-block ;\" alt=\"{5x+9}\/15 = {{5x}\/15} + {9\/15} = {x\/3} + {3\/5}\" title=\"{5x+9}\/15 = {{5x}\/15} + {9\/15} = {x\/3} + {3\/5}\"\/><\/p>\n<p>Another related mistake.  Suppose we have to solve the following equation.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_984_603fe87abb970e36c1dea8ec3e2607bc.png\" style=\"vertical-align:-16px; display: inline-block ;\" alt=\"{1\/16} = {1\/48} + {1\/x}\" title=\"{1\/16} = {1\/48} + {1\/x}\"\/><\/p>\n<p>While it&#8217;s true in general that you can take the reciprocal of both sides, unfortunately, you can only take the reciprocal of a single number or a single fraction, NOT a sum or difference of fractions.<\/p>\n<p><a href=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img4.png\"><img decoding=\"async\" class=\"alignnone size-full wp-image-2749\" title=\"cgmm_img4\" src=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img4.png\" alt=\"\" width=\"215\" height=\"50\" \/><\/a><\/p>\n<p>The reciprocal of a sum is <strong><em>not<\/em><\/strong> the sum of the reciprocals.  How do you find the reciprocal of a sum?  You would have to add the two fractions, using a common denominator, combining them into a single fraction.  Here, by far the easiest solution would be to begin by subtracting 1\/48 from both sides, and performing the fraction subtraction on the left side, so that you have a single fraction equals 1\/x.  Then, you would legitimately be allowed to take the reciprocal of both sides to solve.<\/p>\n<p>&nbsp;<\/p>\n<h2>Distributing a root<\/h2>\n<p>The final mistake, yet another example of illegitimately over-extending the pattern of the Distributive Law, is distributing root signs.  Succinctly, this mistake says:<\/p>\n<p><a href=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img5.png\"><img decoding=\"async\" class=\"alignnone size-full wp-image-2750\" title=\"cgmm_img5\" src=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img5.png\" alt=\"\" width=\"147\" height=\"23\" \/><\/a><\/p>\n<p>You cannot separate a square-root by addition or subtraction.  You can separate a root by multiplication or division: see this post for more on that.  You can see more about roots in general <a href=\"https:\/\/magoosh.com\/gmat\/gmat-quant-roots\/\">here<\/a>.<\/p>\n<p>If you have the equation\u2026<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993.5_561f62add051cb822cc430b356e2ea2a.png\" style=\"vertical-align:-6.5px; display: inline-block ;\" alt=\"y^2 = x^2 + 25\" title=\"y^2 = x^2 + 25\"\/><\/p>\n<p>\u2026 it is illegal to try to simplify that by taking a square-root of each term:<\/p>\n<p><a href=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img6.png\"><img decoding=\"async\" class=\"alignnone size-full wp-image-2751\" title=\"cgmm_img6\" src=\"https:\/\/magoosh.com\/gmat\/files\/2012\/09\/cgmm_img6.png\" alt=\"\" width=\"183\" height=\"23\" \/><\/a><\/p>\n<p>Think about it.  Mr. <a href=\"http:\/\/en.wikipedia.org\/wiki\/Pythagoras\">Pythagoras<\/a> was a very intelligent individual.  If it were possible to simplify <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993.5_04c89863eb01ff5fbccd8c2c6a599726.png\" style=\"vertical-align:-6.5px; display: inline-block ;\" alt=\"a^2 + b^2 = c^2\" title=\"a^2 + b^2 = c^2\"\/> to a + b = c, then that&#8217;s how he would have stated the famous theorem.  The fact is: he had to state it as <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993.5_04c89863eb01ff5fbccd8c2c6a599726.png\" style=\"vertical-align:-6.5px; display: inline-block ;\" alt=\"a^2 + b^2 = c^2\" title=\"a^2 + b^2 = c^2\"\/>, because it is absolutely illegal to simplify that to a + b = c.<\/p>\n<p>In fact, whereas the former is true for the three side of every right triangle, the latter is not true for the three sides of any triangle.  In fact, it constitutes a blatant violation of the <a href=\"https:\/\/magoosh.com\/gmat\/facts-about-ordinary-triangles-on-the-gmat\/\">Triangle Inequality<\/a>, a law that is true for every possible triangle.<\/p>\n<p>When you make a mistake during your GMAT preparation\u2014not just on the Quant section\u2014there&#8217;s always an opportunity to learn from your errors. Check out the video below for tips, then try out the practice questions!<\/p>\n<p><iframe width=\"560\" height=\"315\" src=\"https:\/\/www.youtube.com\/embed\/WnbMhdY9oLo\" style=\"border: 0; margin: 0 auto; display: flex\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture\" allowfullscreen><\/iframe><\/p>\n<p>&nbsp;<\/p>\n<h2>Practice Questions<\/h2>\n<p>1) Find the value of <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_9d4e9155adb8e349bce64ee7041e35da.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"a + b\" title=\"a + b\"\/><\/p>\n<p>(1) <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993.5_794d3c23228e7a247819b6d4ac6b6be3.png\" style=\"vertical-align:-6.5px; display: inline-block ;\" alt=\"a^2 + b^2 = 50\" title=\"a^2 + b^2 = 50\"\/><\/p>\n<p>(2) <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_98e179a4fa14a2fb9801d1549b2cb789.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"a - b = 8\" title=\"a - b = 8\"\/><\/p>\n<ol>\n<li>Statement 1 alone is sufficient but statement 2 alone is not sufficient to answer the question asked.<\/li>\n<li>Statement 2 alone is sufficient but statement 1 alone is not sufficient to answer the question asked.<\/li>\n<li>Both statements 1 and 2 together are sufficient to answer the question but neither statement is sufficient alone.<\/li>\n<li>Each statement alone is sufficient to answer the question.<\/li>\n<li>Statements 1 and 2 are not sufficient to answer the question asked and additional data is needed to answer the statements.<\/li>\n<\/ol>\n<p>&nbsp;<\/p>\n<p>2) Is <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_57b56e490bc55daa2abc60059de83e9a.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"x<sqrt{34}\" title=\"x<sqrt{34}\"\/>?<\/p>\n<p>(1) <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_b58fbdc11bf91fe94a395538cef57bef.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"x<sqrt{33}+1\" title=\"x<sqrt{33}+1\"\/><\/p>\n<p>(2) <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_c942909ce03e4f48b5a07531800baa96.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"x< 5 + 3\" title=\"x< 5 + 3\"\/><\/p>\n<ol>\n<li>Statement 1 alone is sufficient but statement 2 alone is not sufficient to answer the question asked.<\/li>\n<li>Statement 2 alone is sufficient but statement 1 alone is not sufficient to answer the question asked.<\/li>\n<li>Both statements 1 and 2 together are sufficient to answer the question but neither statement is sufficient alone.<\/li>\n<li>Each statement alone is sufficient to answer the question.<\/li>\n<li>Statements 1 and 2 are not sufficient to answer the question asked and additional data is needed to answer the statements.<\/li>\n<\/ol>\n<p>&nbsp;<\/p>\n<h2>Practice Question Answers and Explanations<\/h2>\n<p>(1) E; (2) E<\/p>\n<p>In both of those questions, I was bending over backwards trying to lead you into making one of those errors.<\/p>\n<p>&nbsp;<\/p>\n<p>1)  Clear prompt: find the value of <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_9d4e9155adb8e349bce64ee7041e35da.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"a + b\" title=\"a + b\"\/>.<\/p>\n<p><strong>Statement #1<\/strong>: We <em><span style=\"text-decoration: underline;\">cannot<\/span><\/em> take the square root of <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993.5_b4d689e488d639f11f0fbcde6b63ca1e.png\" style=\"vertical-align:-6.5px; display: inline-block ;\" alt=\"a^2 + b^2\" title=\"a^2 + b^2\"\/> to get <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_9d4e9155adb8e349bce64ee7041e35da.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"a + b\" title=\"a + b\"\/>.  There&#8217;s no way to simplify <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993.5_b4d689e488d639f11f0fbcde6b63ca1e.png\" style=\"vertical-align:-6.5px; display: inline-block ;\" alt=\"a^2 + b^2\" title=\"a^2 + b^2\"\/>, and the equation <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993.5_794d3c23228e7a247819b6d4ac6b6be3.png\" style=\"vertical-align:-6.5px; display: inline-block ;\" alt=\"a^2 + b^2 = 50\" title=\"a^2 + b^2 = 50\"\/> has an infinite number of pairs (a, b) that solve it, each with a different sum.  This statement does not allow us to answer the question.  Statement #1 is insufficient.<\/p>\n<p><strong>Statement #2<\/strong>: Again, there are an infinite number of pairs (a, b) that satisfy the equation <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_98e179a4fa14a2fb9801d1549b2cb789.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"a - b = 8\" title=\"a - b = 8\"\/>.  No conclusion can be drawn about <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_9d4e9155adb8e349bce64ee7041e35da.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"a + b\" title=\"a + b\"\/>.  Statement #2 is insufficient.<\/p>\n<p><strong>Statements #1 &amp; #2 Combined<\/strong>:  Now, we have two equations for two unknowns, so we can solve.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_fe3a5a1b80e0a3dffb197b89a8fb2fc8.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"a-b=8 right a=b+8\" title=\"a-b=8 right a=b+8\"\/><\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_990.5_1588cc9875ea76b1c520930df5f7d8df.png\" style=\"vertical-align:-9.5px; display: inline-block ;\" alt=\"a^2+b^2=50 right (b+8)^2+b^2=50\" title=\"a^2+b^2=50 right (b+8)^2+b^2=50\"\/><\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993.5_d8423843449ee06d7f3dd5e2974c6da2.png\" style=\"vertical-align:-6.5px; display: inline-block ;\" alt=\"b^2+16b+64+b^2=50\" title=\"b^2+16b+64+b^2=50\"\/><\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993.5_1e1f599cc340e3f7defe0270d320609c.png\" style=\"vertical-align:-6.5px; display: inline-block ;\" alt=\"2*b^2+16b+14=0\" title=\"2*b^2+16b+14=0\"\/><\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993.5_df1ed19fa1f31d25dc6f9b4d03106cb7.png\" style=\"vertical-align:-6.5px; display: inline-block ;\" alt=\"b^2+8b+7=0\" title=\"b^2+8b+7=0\"\/><\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_990.5_209e5518ce7f3cfd6b25a00bbb0261b6.png\" style=\"vertical-align:-9.5px; display: inline-block ;\" alt=\"(b+1)(b+7)=0\" title=\"(b+1)(b+7)=0\"\/><\/p>\n<p><img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_9ea6131140189ec34bee6d5a582dc6ad.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"b=-1\" title=\"b=-1\"\/><br \/>\n<img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_d3a51f7c7272eb903083af415d03ae54.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"b=-7\" title=\"b=-7\"\/><\/p>\n<p>Two solutions: {a = +7, b = -1} or {a = +1, b = -7}.<\/p>\n<p>These two have different sums, so we cannot uniquely determine the value of a + b.  Even combined, the statements are insufficient.<\/p>\n<p>Answer = <strong>E<\/strong>.<\/p>\n<p>&nbsp;<\/p>\n<p>2) The prompt: Is <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_57b56e490bc55daa2abc60059de83e9a.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"x<sqrt{34}\" title=\"x<sqrt{34}\"\/>?<\/p>\n<p><strong>Statement #1<\/strong>: We <em><span style=\"text-decoration: underline;\">cannot<\/span><\/em> say that <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_76a9ba48c8c9c4bb4c8e789c8e7b4fe3.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"sqrt{34}\" title=\"sqrt{34}\"\/> is equal to <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_d61c58e0c5c75cd5516fa661794b5e0e.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"1 + sqrt{33}\" title=\"1 + sqrt{33}\"\/>.  Like <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_76a9ba48c8c9c4bb4c8e789c8e7b4fe3.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"sqrt{34}\" title=\"sqrt{34}\"\/>, <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_cb51b8d701f319f4f7deaa8ef7db2b2e.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"sqrt{33}\" title=\"sqrt{33}\"\/> is somewhere between 5 and 6.  When we add 1, it&#8217;s somewhere between 6 and 7.  If we know x is less than a number between 6 and 7, that&#8217;s not a guarantee that it&#8217;s less than a number between 5 and 6.  Statement #1 is insufficient.<\/p>\n<p><strong>Statement #2<\/strong>: We <em><span style=\"text-decoration: underline;\">cannot<\/span><\/em> say that <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_76a9ba48c8c9c4bb4c8e789c8e7b4fe3.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"sqrt{34}\" title=\"sqrt{34}\"\/> is equal to <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_ceae8c96e07b8b2871111eee22be8f99.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"sqrt{25} + sqrt{9} = 5 + 3\" title=\"sqrt{25} + sqrt{9} = 5 + 3\"\/>.  Knowing that <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_d153c18125bbda3285077988f2fba935.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"x<8\" title=\"x<8\"\/> doesn&#8217;t tell us conclusively whether or not x is less than <img decoding=\"async\" src=\"https:\/\/magoosh.com\/gmat\/wp-content\/plugins\/wpmathpub\/phpmathpublisher\/img\/math_993_76a9ba48c8c9c4bb4c8e789c8e7b4fe3.png\" style=\"vertical-align:-7px; display: inline-block ;\" alt=\"sqrt{34}\" title=\"sqrt{34}\"\/>, a number between 5 and 6.  Statement #2 is insufficient.<\/p>\n<p><strong>Statements #1 &amp; #2 Combined<\/strong>: Now, the combined conditions just amount to Statement #1, which was more restrictive than Statement #2.  We already know that Statement #1 is insufficient, so this means that the combined statements are also insufficient.<\/p>\n<p>Answer = <strong>E<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p>For more practice questions, sign up for <a href=\"http:\/\/gmat.magoosh.com\" target=\"_blank\" rel=\"noopener noreferrer\">Magoosh GMAT Prep<\/a>, which offers hundreds of lessons and practice questions, all with video explanations!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Learn the cluster of the most common GMAT math mistakes, mistakes that the exam regularly exploits so you can avoid these pitfalls. &nbsp; Pattern-Matching, Good and Bad The human brain is, far and away, the best pattern-matching machine we have ever seen. No computer comes close. We match patterns for all kinds of things: facial [&hellip;]<\/p>\n","protected":false},"author":26,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[112],"tags":[],"ppma_author":[13209],"class_list":["post-9203","post","type-post","status-publish","format-standard","hentry","category-math"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v21.7 (Yoast SEO v21.7) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Common GMAT Math Mistakes - Magoosh Blog \u2014 GMAT\u00ae Exam<\/title>\n<meta name=\"description\" content=\"Making GMAT math mistakes is a bummer, but it can be avoided! 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