Here is a rundown of geometry facts you might need to know about circles for the GMAT.

## The Basic Terminology

A circle is the set of all points equidistant from a fixed point. That means a circle is this:

and not this:

Photo by cliparts.co

In other words, the circle is only the curved round edge, not the middle filled-in part. A point on the edge is “on the circle”, but a point in the middle part is “in the circle” or “inside the circle.” In the diagram below,

point A is on the circle, but point B is in the circle.

By far, the most important point in the circle is the **center** of the circle, the point equidistance from all points on the circle.

## Chords

Any line segment that has both endpoints on the circle is a **chord**.

By the way, the word “chord” in this geometric sense is actually related to “chord” in the musical sense: the link goes back to Mr. Pythagoras (c. 570 – c. 495 BCE), who was fascinated with the mathematics of musical harmony.

If the chord passes through the center, this chord is called a **diameter**. The diameter is a chord. A diameter is the longest possible chord. A diameter is the only chord that includes the center of the circle.

The diameter is an important length associated with a circle, because it tells you the maximum length across the circle in any direction.

An even more important length is the **radius**. A radius is any line segment with one endpoint at the center and the other on the circle.

As is probably clear visually, the radius is exactly half the diameter, because a diameter can be divided into two radii. The radius is crucially important, because if you know the radius, it’s easy to calculate not only the diameter, but also the other two important quantities associated with a circle: the circumference and the diameter.

## Circle Formulas

The **circumference** is the length of the circle itself. This is a curve, so you would have to imagine cutting the circle and laying it flat against a ruler. As it turns out, there is a magical constant that relates the diameter (d) & radius (r) to the circumference. Of course, that magical constant is . From the very definition of

If you remember the second, more common form, you don’t need to know the first. The number

These two formulas follow from the definition of **area of circle** was discovered by one brilliant mathematician, and everyone on earth has this one man to thank for his formula for the area of a circle. That man was Archimedes (c. 287 – c. 212 BCE). Here is Archimedes’ amazing formula:

This is another formula you need to know cold on test day.

In the next post in this series, I’ll discuss circles and angles. Here is the whole series:

1) Introduction to Circles on the GMAT

2) GMAT Geometry: Circles and Angles

3) Circle and Line diagrams on the GMAT

4) Inscribed and Circumscribed Circles and Polygons on the GMAT

5) Slicing up GMAT Circles: Arclengths, Sectors, and Pi

Finally, here are some practice problems.

## Practice Problems

1) Given that a “12-inch pizza” means circular pizza with a diameter of 12 inches, changing from an 8-inch pizza to a 12-inch pizza gives you approximately what percent increase in the total amount of pizza?

(A) 33

(B) 50

(C) 67

(D) 80

(E) 125

2) What is the diameter of circle Q?

Statement #1 — the circumference of Q is

Statement #2 — the area of Q is

## Practice Problem Solutions

1) The 8-inch pizza has a radius of r = 4, so the area is **E**.

2) Statement #1: if you know the circumference, then you can use

Statement #2: if you know the area, you can find the radius, and then double that to get the diameter. This statement by itself is also sufficient.

Both statements alone are sufficient. Answer = **D**.

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Hi Mike,

Just wondering, is there any useful formulas for chords? for example you have a circle, and there is a chord equal to the radius (so for visualization purposes this could make an equilateral triangle with two other radii). Is there a formula or method to calculate the area between the chord and the smaller arc of the circle?

Wait… I think I solved my own question. the area I am talking about is basically the difference between the area of a 60 degree arc and an equilateral triangle…

area of 60 deg arc = (pi*r^2/6)

Area of equilateral triangle of side r = (sqrt(3)/4)*r

—> area between radius sized cord and outside of circle = (pi*r^2/6) – (sqrt(3)/4)*r = (2*pi*r^2 – 3r)/12

Please let me know if I have gone about this the right way. Still not sure if this is correct.

Dear DropBear,

I’m happy to respond. 🙂 Notice that, in the formula for the area of an equilateral triangle, as in any area formula, we need a factor of length squared. Here, the r needs to be squared. Also, you seem to have lost the radical 3 in the final formula.

Here’s what I am going to say. Even if you had gotten the perfect formula, that formula is virtually useless. Unless the GMAT happens to ask about that very specific case, this result is useless. What is incredibly valuable is your ability to think through situations such as this. Forget the final result formulas, which are useless, but value your ability to think through unique mathematical situations.

Does this distinction make sense?

Mike 🙂

Shouldn’t c= 2*pi*r instead of c= 2*pi*d in above?

Serena,

YES! ABSOLUTELY CORRECT! Yes, that was a typo, and I just corrected it. Thank you very much for pointing this mistake out. Best of luck to you, my friend.

Mike 🙂

Mike,

I am wondering why answer to Question 1 is not choice B(50)

This is how I was calculating:-

If original diameter was 8, then increase in diameter is by 4 (8 inch changed to 12 inch)

This means if original diameter was 100 then increase in diameter would be by amount of (100*4)/8=50

Hence % increase is 50%

Could you please let me know where am I thinking wrong?

Thanks

Peter,

You fell into the classic GMAT pizza-math trap. The numbers 8 & 12 are diameters — they’re lengths. By contrast, “amount of pizza”, how much you can eat, is AREA, not length. That’s why we need to figure out the areas corresponding to d = 8 and d = 12, and base the percents on those areas.

Mike 🙂

Oh I see…:-)

Thanks Mike. Appreciate you reply.

You are more than welcome, my friend. Best of luck to you!

Mike 🙂