If is an non-negative integer and is a divisor of then =

A.
B.
C.
D.
E.

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For divisibility by 15, the number should be divisible by both 3 and 5.
Checking divisibility by 3, we find that it is not divisible. Because 7 + 5 + 9 + 3 + 2 + 5 = 31 which is not divisible by 3. Hence 15 or any multiple of 15 cannot divide that number exactly. Hence the only possible solution is k = 0.

The answer is B.
As 15 is not a divisor of 759325, neither are any powers of 15.
Therefore k is 0. 15^1 is 1, which is a divisor of 759325.
3^0 – 0^3 = 1

Ans is 1.
15 Power 1 is 15 and it is not a divisor of the given number.And hence the higher power of 15 will not be a divisor of the given number. For instance, If we take 15 power 5, the value is 759,375.
Therefore the only possibility is 15 Power 0 is 1 and we know that 1 is a divisor for all the numbers. The value of K is 0.
Substituting this, we have (3^0)-(0^3) ans it is simplified as 1-0=1. Hence the solution is arrived.

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Answer:

(B) 1

Explanation:

For divisibility by 15, the number should be divisible by both 3 and 5.

Checking divisibility by 3, we find that it is not divisible. Because 7 + 5 + 9 + 3 + 2 + 5 = 31 which is not divisible by 3. Hence 15 or any multiple of 15 cannot divide that number exactly. Hence the only possible solution is k = 0.

If k = 0, then 3^0 – 0^3 => 1 – 0 => 1

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The answer is B.

As 15 is not a divisor of 759325, neither are any powers of 15.

Therefore k is 0. 15^1 is 1, which is a divisor of 759325.

3^0 – 0^3 = 1

Ans is 1.

15 Power 1 is 15 and it is not a divisor of the given number.And hence the higher power of 15 will not be a divisor of the given number. For instance, If we take 15 power 5, the value is 759,375.

Therefore the only possibility is 15 Power 0 is 1 and we know that 1 is a divisor for all the numbers. The value of K is 0.

Substituting this, we have (3^0)-(0^3) ans it is simplified as 1-0=1. Hence the solution is arrived.