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GRE Geometry: Practice Question of the Week #31

Here’s this week’s practice question– we’ll be posting the answer and explanation tomorrow, good luck!

A cow is tethered to the corner of a shed. If the length of the rope is 5, and the shed has length 4 and width 3, what is the maximum area that is accessible to the cow? (The cow cannot go inside the shed).

  1. 12pi
  2. 15pi
  3. 16pi
  4. 18pi
  5. 20pi
Update: Here’s theĀ answer/explanation post!

About the Author

Margarette Jung graduated from UC Berkeley as a double major in English Literature and Linguistics. She has been teaching for large companies and tutoring privately for more than 5 years. Follow her on Google+!

4 Responses to GRE Geometry: Practice Question of the Week #31

  1. Shubham June 24, 2012 at 6:41 am #


    We can solve this question without finding out exact value as well.

    Total area of circle = 25p

    Now the area covered by cow should be = 3/4 of total area of circle + some small areas near the rectangle .i.e 18p + something.

    Option gives only one such value that is 20p.

    I am writing GRE in August.

    • Chris Lele
      Chris June 26, 2012 at 2:22 pm #

      Yes, great way of thinking! And a great way to save time.

      It’s exactly this logic that will help you do well test day :).

  2. Adrian December 26, 2011 at 11:18 pm #

    Its E, 20 pi

    • Chris Lele
      Chris June 26, 2012 at 2:21 pm #

      Good job :)

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