offers hundreds of practice questions and video explanations. Go there now.
Sign up or log in to Magoosh GMAT Prep.

GMAT Quant: Coordinate Geometry Practice Questions

For more information on Coordinate Geometry on the GMAT, see these articles:

1) Quadrants in the x-y Plane

2) Special Properties of y = x

3) Distance between Two Points

4) Slopes

5) Midpoints and Parallel & Perpendicular lines


Here are five new practice problems on these topics.

1. The center of circle Q is on the y-axis, and the circle passes through points (0, 7) and (0, –1).  Circle Q intersects the positive x-axis at (p, 0).  What is the value of p?




2. In the diagram above, coordinates are given for three of the vertices of quadrilateral ABCD.  Does quadrilateral ABCD have an area greater than 30?

Statement #1: point B has an x-coordinate of 4

Statement #2: quadrilateral ABCD is a parallelogram

3. In the x-y plane, point F = (3, –2).   Point G is at (3, k), where k is an integer such that 5 ≤ k ≤ 40.  If FG is to form the side of a square, how many different square can be created?

    (A) 35
    (B) 36
    (C) 70
    (D) 72
    (E) 140


4. In the coordinate system above, which of the following is the equation of line p?

    (A) 3x + 7y = 18
    (B) 7x + 3y = 18
    (C) 3x – 7y = 18
    (D) 7x – 3y = 18
    (E) 3x + 7y = –18


5. The graph above shows line H.  Line J (not shown) does not pass through the first quadrant.  Which of the following could be true?

I.  line J is perpendicular to line H

II.  line J is parallel to line H

III.  line J intersect line H in the third quadrant

    (A) I only
    (B) II only
    (C) I and II only
    (D) I and III only
    (E) I, II, and III

If would like to express anything, or have any question, please let us know in the comments section below!

Solutions to the Practice Problems

1) The center of the circle must be halfway between (0, 7) and (0, –1), at the point C =  (0, 3).  We know the radius is 4.  Now consider what this looks like:


Here C = (0, 3) is the center.  From C to (0, 7) is a radius of 4, and from C to (0, –1) is also a radius of 4.  Well, AC is another radius, so this also has a length AC = 4.  Notice, now, that OCA is a right triangle.  We know that OC = 3 and AC = 4


Answer = D

2) In this problem, the lower triangle ACD has a base of AC = 8, and a height, from the origin down to D, of 4.  Therefore, the area of ACD = (1/2)(b)(h) = (1/2)(8)(4) = 16.  We would need to know something about the upper triangle ABC to know the answer to the prompt question.  We know the base of triangle ABC, AC = 8, but we don’t know anything about the height.

Statement #1: if we know the x-coordinate of point B, that doesn’t help us.  We still know the base AC = 8, but we don’t know the height, only the vertical line along which point B will lie.  Any height could be possible.  This statement, alone and by itself, is insufficient.

Statement #2: the diagonal of any parallelogram (i.e. the line connecting two opposite vertices) divides it into two congruent triangles.  Well, if ABCD is a parallelogram, then line AC is a diagonal, which means triangles ADC and ABD must be congruent and have equal area.  This would allow us to calculate the total area and answer the prompt question.   This statement, alone and by itself, is sufficient.

Answer = B

3) Idea #1: inclusive counting.   From 5 to 40 inclusive, there are not 35, but 36 values.

Idea #2: The points F & G have the same x-coordinates, so FG must be a vertical segment.

There are 36 possible vertical segments.  Any square with sides parallel to the x- & y-axes has two vertical sides and two horizontal sides.   The vertical segment FG could be the right side or the left side of the square, so for any vertical segment there are two possible squares.

(36 segments) x (2 possible squares) = 72 squares

Answer = D

4) First of all, line p clearly has a negative slope.  If the slope is negative, that means the x & y have opposite sign coefficients when written in slope-intercept form (i.e. y = mx + b).  Thus, if we move the x to the opposite side, so that the x & y are on the same side, then they will have to have the same sign coefficients.  The x & y coefficients could be both positive or both negative.  The latter is not an option among the answer choices.   We must have a plus-sign, so answers (C) & (D) are out right away.

Notice the x intercept is approximately (6, 0) —- it could be exactly equal to that, or approximately equal to that.  Plug this in to the three remaining choices, and see what happens.

(A) 3(6) + 7(0) = 18 YES, exactly true

(B) 7(6) + 3(0) ≠ 18 no, not even close

(E) 3(6) + 7(0) = –18 no, not even close

Answer = A

5) If line J does not pass through first quadrant, then it must be a line with a negative slope and a negative y-intercept.  Such a line could be perpendicular to line H:


Therefore, Statement I is possible.

Line H has a positive slope, and line J must have a negative slope, so there is absolutely no way for them to have the same slope.  They absolutely cannot be parallel.  Therefore, Statement II is impossible.

Both line H and line J pass through QIII, so there’s no reason they cannot intersect there.  For example:


Therefore, Statement III is possible.

Answer = D


By the way, sign up for our 1 Week Free Trial to try out Magoosh GMAT Prep!

3 Responses to GMAT Quant: Coordinate Geometry Practice Questions

  1. Evelyn Asiedu July 30, 2016 at 1:14 am #

    Hi Mike,
    Your note has really help me understand a lot of things. However, I have realized you are able to tell whether the slope is positive or negative. Can you help understand how you able to know the sign of the slope from the diagram? ?

    • Magoosh Test Prep Expert
      Magoosh Test Prep Expert August 9, 2016 at 2:00 pm #

      Hi Evelyn,

      When looking at a graph, you can always tell the sign of a slope just by looking at the line! If the line moves upward from left to right, the slope is positive. If the line moves downward from left to right, the slope is negative. I like to think of it like this: picture a person walking along the line from left to right. If he is walking uphill it is a positive slope, if he is walking downhill it is a negative slope 🙂

  2. Kristen December 10, 2015 at 11:26 am #

    Hi, Mike!! Thanks for the awesome review and questions. I was working on 1 and used the distance formula to try and find (p, 0). I guess I fell into the trap answer C :). But, why can’t I use the distance formula here?? Thanks a bunch!!!

Magoosh blog comment policy: To create the best experience for our readers, we will only approve comments that are relevant to the article, general enough to be helpful to other students, concise, and well-written! 😄 Due to the high volume of comments across all of our blogs, we cannot promise that all comments will receive responses from our instructors.

We highly encourage students to help each other out and respond to other students' comments if you can!

If you are a Premium Magoosh student and would like more personalized service from our instructors, you can use the Help tab on the Magoosh dashboard. Thanks!

Leave a Reply